标题:
功能很全的单片机电子密码锁Proteus仿真与源码分享
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作者:
883
时间:
2018-4-20 17:51
标题:
功能很全的单片机电子密码锁Proteus仿真与源码分享
电子密码锁仿真原理图如下(proteus仿真工程文件可到本帖附件中下载)
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资料包:
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密码锁的单片机源程序如下:
/********
1.按键说明: 按键K1~K3为数字"1~3",K5~K7为数字"4~6",K9~K11为数字"7~9",
K13为"0",K14为设置键,K15为取消键,K16为回车键.
2.程序说明: 按数字键输入正确密码,回车确定.LED亮.否则5次错误,蜂鸣器响.按键暂时失效.
按设置键进入修改密码,先输入旧密码,再输入两次新密码,回车确定.
关电后密码自动保存.
3.使用说明: 先找到程序中"E2Read(num0,0x05,sizeof(num0));"语句屏蔽后下载到单片机,
操作一次密码设置(初始密码为"0"),以清除EEPROM内原有数据,关电.解除屏蔽再下载. **********/
#include "Lcd1602.h"
#include "Key.h"
#include "Eeprom.h"
bit BeedOn = 0; //蜂鸣器标志
bit set = 0; //设置标志
bit On = 0; //密码打开标志
bit clag = 0; //清除输入指针标志
uchar Paserror = 0; //密码错误次数
uchar Passcou = 0; //更改密码引索
uchar T0RH=0,T0RL=0;
uchar num0[8],num1[8],num2[8];
void ConfigTime0(uchar ms);
void main()
{
EA = 1;
ConfigTime0(2);
Lcd1602Init();
E2Read(num0,0x05,sizeof(num0));
LcdShowStr(0,0,"Please input...");
while(1)
{
KeyDriver();
}
}
void InCoumNum(uchar *buf,uchar n) //输入数据
{
static uchar i;
if (clag)
{
i = 0;
clag = 0;
}
if (i < 8)
{
buf[i] = n;
i++;
LcdShowStr(16-i,1,"*");
}
else
i = 0;
}
bit ContNum(uchar *dat1,uchar *dat2) //对比数据
{
uchar i;
for (i=0;i<8;i++)
{
if (*dat1++ != *dat2++)
return 0;
}
return 1;
}
void ClsNum(uchar *dat) //清除数据
{
uchar i;
for (i=0;i<8;i++)
{
*dat++ = 0;
}
}
void CopyNum(uchar *dat1,uchar *dat2) //复制数据
{
uchar i;
for (i=0;i<8;i++)
{
*dat1++ = *dat2++;
}
}
void PasErrCou() //密码错误次数显示
{
uchar str[1];
Paserror++;
str[0] = Paserror+'0';
LcdShowStr(0,1,"ERROR");
LcdShowStr(6,1,str);
if (Paserror >= 5)
{
BeedOn = 1;
}
}
void SetPass()
{
if (!On && !set)
{
LcdClsFull();
LcdShowStr(0,0,"Set the Passwor");
set = 1;
}
}
void Esc() //复位
{
Passcou = 0;
On = 0;
set = 0;
BeedOn = 0;
Pout = 1;
clag = 1;
ClsNum(num1);
ClsNum(num2);
}
void Enter()
{
if (!set)
{
if (!ContNum(num1,num0))
{
ClsNum(num1);
LcdClsStr(0,1,16);
PasErrCou();
}
else
{
LcdClsFull();
LcdShowStr(0,0,"Welcome to use!");
LcdShowStr(0,1,"Turn ON");
ClsNum(num1);
Paserror =0;
Pout = 0;
On = 1;
}
}
else
{
switch (Passcou)
{
case 0: if (ContNum(num1,num0)) //密码输入正确
{
LcdClsFull();
LcdShowStr(0,0,"Enter the new");
ClsNum(num1);
Passcou = 1;
}
else //密码输入错误清除输入数
{
ClsNum(num1);
LcdClsStr(0,1,16);
PasErrCou();
}
break;
case 1: LcdClsFull();
LcdShowStr(0,0,"Enter new too");
Passcou = 2;
break;
case 2: if (ContNum(num1,num2))
{
LcdClsFull();
LcdShowStr(0,0,"Set pass OK ");
CopyNum(num0,num2);
E2Write(num0,0x05,sizeof(num0));
Esc();
}
else
{
ClsNum(num2);
LcdClsStr(0,1,16);
}
default: break;
}
}
clag = 1;
}
void KeyAction(uchar kcod)
{
if (Paserror < 5)
{
if ((kcod >= 0x00) && (kcod <= 0x09))
{
if (!On) //密码打开状态禁止输入
{
switch(Passcou)
{
case 0: InCoumNum(num1,kcod); //输入数字
break;
case 1: InCoumNum(num1,kcod);
break;
case 2: InCoumNum(num2,kcod);
break;
default:
break;
}
}
}
else if (kcod == 0x1b)
{
if (!On)
SetPass(); //设置密码
}
else if (kcod == 0x0d) //复位
{
LcdClsStr(0,1,16);
LcdShowStr(0,0,"Please input...");
Esc();
}
else if (kcod == 0x27)
{
if (!On)
Enter(); //确认
}
}
}
void ConfigTime0(uchar ms)
{
ulong tmp;
tmp = 11059200/12;
tmp = (tmp*ms)/1000;
tmp = (65536-tmp);
T0RH = (uchar)(tmp>>8);
T0RL = (uchar)tmp;
TH0 = T0RH;
TL0 = T0RL;
TMOD &= 0xf0;
TMOD |= 0x01;
TR0 = 1;
ET0 = 1;
}
void InterruptTime0() interrupt 1
{
static uint Errortime = 0; //密码错误计时
TH0 = T0RH;
TL0 = T0RL;
KeyScan();
if (BeedOn)
Bee = ~Bee;
else
Bee = 1;
if (Paserror >= 5)
……………………
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作者:
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时间:
2019-5-20 21:21
解决了我仿真不出图的问题
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