数控直流稳压电源proteus仿真+程序资料 -

标题: 数控直流稳压电源proteus仿真+程序资料 [打印本页]

作者: zqsong 时间: 2018-11-16 16:34
标题: 数控直流稳压电源proteus仿真+程序资料
#include<reg51.h>
#include<absacc.h>
#define  dac0832 XBYTE[0X7fff]
unsigned char code shu[]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90};
float s;
sbit ALE=P3^0;
sbit START=P3^1;
sbit EOC=P3^2;
sbit OE=P3^3;
sbit SHCP=P2^0;
sbit DS=P2^1;
sbit STCP=P2^2;
sbit P11=P3^5;
sbit P12=P3^7;
sbit clk=P2^6;
unsigned char j,k,m,n,i,a;
unsigned int b;
void delay(unsigned char t)
{  while(t--);
}
void display()
{

  j=0x01;
  for(i=0;i<8;i++)
  { if((shu[m]&j)==0)
   { DS=0;}
   else {DS=1;}
SHCP=1;
SHCP=0;
   j<<=1;
}
P12=0;
P11=1;



STCP=0;
STCP=1;
delay(200);
j=0x01;
for(i=0;i<8;i++)
   { if((shu[n]&j)==0)
   { DS=0;}
else {DS=1;}
   SHCP=1;
SHCP=0;
   j<<=1;
}
   P11=0;
P12=1;

   STCP=0;
STCP=1;
delay(200);
   }

void main()
{
P2=0X87;
TMOD=0X20;
TH1=0X06;
TL1=0X06;
EA=1;
ET1=1;
TR1=1;

while(1)
{
ALE=1;
ALE=0;
START=1;
START=0;
while(EOC==0);
OE=1;
k=P1;
a=P1;
b=a*6;
m=b/1000;
n=b%1000/100;

dac0832=k;

display();

}
}
void  time() interrupt 3
  {
   clk=!clk;
}

360截图16751105118112104.png (161.12 KB, 下载次数: 36)

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