给大家分享下个编程的帮手_C流程快速转换 -

标题: 给大家分享下个编程的帮手_C流程快速转换 [打印本页]

作者: jinsheng7533967 时间: 2018-12-8 21:01
标题: 给大家分享下个编程的帮手_C流程快速转换

C流程快速转换.rar (973.67 KB, 下载次数: 15)

图片是下面代码自动生成的效果，代码较大时能快速理清程序架构

#include <reg52.h>
#include <intrins.h>
#define uint unsigned int
#define uchar unsigned char
sbit ser=P1^0;
sbit sck=P1^1;
sbit rck=P1^2;
sbit lcdrs=P1^4;
sbit lcdrw=P1^5;
sbit lcden=P1^6;

sbit dat=P2^2;
sbit sclk=P2^1;
sbit cs=P2^0;

sbit rled=P2^6;
sbit gled=P2^7;
uchar e,f,g;

void delay(uint a)
{
      uint x,y;
      for(x=a;x>0;x--)
      for(y=110;y>0;y--);
}
  unsigned char code table[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f};
void timeinit()
{
      TMOD=0x21;
      TH1=0XFD;
      TH1=0XFD;
      TH0=(65536-50000)/256;
      TL0=(65536-50000)%256;
      EA=1;
      TR1=1;

      ET0=1;       TR0=1;
}

uchar adc0831()
{
      uint i,temp;
         dat=1;
      _nop_();
      _nop_();             sclk=0;
      _nop_();
      _nop_();
      cs=0;
      _nop_();
      _nop_();

      sclk=1;
      _nop_();
      _nop_();
      sclk=0;
      _nop_();
      _nop_();
      sclk=1;
      _nop_();
      _nop_(); sclk=0;
      for(i=0;i<8;i++)
      {

            _nop_();
            _nop_();
            temp=temp<<1;
            if(dat)
            temp=temp|dat;
            sclk=1;
            _nop_();
            _nop_();
            sclk=0;
      }
      cs=1;
      return (temp);
}

void lcdwrite_com(uchar com)
{
      lcdrs=0;
      lcdrw=0;
      P0=com;
      delay(15);
      lcden=1;
      delay(15);
      lcden=0;
}
void lcdwrite_date(uchar date)
{
      lcdrs=1;
      lcdrw=0;
      P0=date;
      delay(15);
      lcden=1;
      delay(15);
      lcden=0;
}
void lcd1602_init()
{
      lcden=0;
      lcdwrite_com(0x38);
      lcdwrite_com(0x0f);
      lcdwrite_com(0x06);
      lcdwrite_com(0x01);
      lcdwrite_com(0x80);
}
void lcd1602_gd()
{
      lcdwrite_date(0x30+1);lcdwrite_com(0x80+0x01);lcdwrite_date(':');
      lcdwrite_com(0x80+0x07);lcdwrite_date('v');
      lcdwrite_com(0x80+0x09);
      lcdwrite_date(0x30+2);       lcdwrite_com(0x80+0x0a);lcdwrite_date(':');
      lcdwrite_com(0x80+0x40);
      lcdwrite_date(0x30+3);       lcdwrite_com(0x80+0x41);lcdwrite_date(':');
      lcdwrite_com(0x80+0x49);
      lcdwrite_date(0x30+4);       lcdwrite_com(0x80+0x4a);lcdwrite_date(':');
}
void lcd1602_ry()
{
uint i,ad,jg1,jg2,jg3,jg4;
      ad=adc0831();
//       ad=ad/51*100;
      jg1=ad/51;
      jg2='.';
      jg3=ad%51*10/51;
      jg4=ad%51*10%51*10/51;

      lcdwrite_com(0x80+0x03);
      lcdwrite_date(0x30+jg1);
      lcdwrite_date(jg2);
      lcdwrite_date(0x30+jg3);
      lcdwrite_date(0x30+jg4);

}
void senddata(uchar a)
{
      uchar x,i;
      x=a;
      for(i=0;i<8;i++)
      {
               ser=(bit)(x&0x80);
            x=x<<1;
            sck=0;
            delay(1);
            sck=1;
      }
      rck=0;
      delay(1);
      rck=1;
}
void main()
{
timeinit();
      lcd1602_init();
      lcd1602_gd();       //  lcd1602_ry();
      while(1)
      {
      senddata(table[f]);
            if((f%2)==0)
            {
                     rled=1;
                     gled=0;
            }
            else
            {
                     rled=0;
                     gled=1;
            }
//
      if(f) lcd1602_ry();//while(1);
      }
}

void time0()interrupt 1
{
      TH0=(65536-50000)/256;
      TL0=(65536-50000)%266;
      e++;  g=!g;
      if(e>=20)
      {
            e=0;
            f++;

            if(f>9)f=0;
      }
}

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