如何加个按键使单片机程序开始计时？ -

标题: 如何加个按键使单片机程序开始计时？ [打印本页]

作者: ajt 时间: 2018-12-21 11:48
标题: 如何加个按键使单片机程序开始计时？
#include <reg52.h>

sbit ADDR0 = P1^0;
sbit ADDR1 = P1^1;
sbit ADDR2 = P1^2;
sbit ADDR3 = P1^3;
sbit ENLED = P1^4;

unsigned char code LedChar[] = {
0xC0, 0xF9, 0xA4, 0xB0, 0x99, 0x92, 0x82, 0xF8,
0x80, 0x90, 0x88, 0x83, 0xC6, 0xA1, 0x86, 0x8E
};
unsigned char LedBuff[6] = {
0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF
};
unsigned char i = 0;
unsigned int cnt = 0;
unsigned char flag1s = 0;

void main()
{
char j;  //Ñ-»·±äá¿
unsigned long sec = 170665;
unsigned char buf[6];

EA = 1;
ENLED = 0;
ADDR3 = 1;
TMOD = 0x10;
TH1  = 0xFC;
TL1  = 0x67;
ET1  = 1;
TR1  = 1;

while (1)
{
      if (flag1s == 1)
      {
         flag1s = 0;
         sec--;

         buf[0] = sec%10;
         buf[1] = sec/10%10;
         buf[2] = sec/100%10;
         buf[3] = sec/1000%10;
         buf[4] = sec/10000%10;
         buf[5] = sec/100000%10;

         for (j=5; j>=1; j--)
         {
            if (buf[j] == 0)
                  LedBuff[j] = 0xFF;
            else
                  break;
         }

         for ( ; j>=0; j--)
         {
            LedBuff[j] = LedChar[buf[j]];
         }
      }
}
}
void InterruptTimer1() interrupt 3
{
TH1 = 0xFC;
TL1 = 0x67;
cnt++;
if (cnt >= 500)
{
      cnt = 0;
      flag1s = 1;
}

P0 = 0xFF;
switch (i)
{
      case 0: ADDR2=0; ADDR1=0; ADDR0=0; i++; P0=LedBuff[0]; break;
      case 1: ADDR2=0; ADDR1=0; ADDR0=1; i++; P0=LedBuff[1]; break;
      case 2: ADDR2=0; ADDR1=1; ADDR0=0; i++; P0=LedBuff[2]; break;
      case 3: ADDR2=0; ADDR1=1; ADDR0=1; i++; P0=LedBuff[3]; break;
      case 4: ADDR2=1; ADDR1=0; ADDR0=0; i++; P0=LedBuff[4]; break;
      case 5: ADDR2=1; ADDR1=0; ADDR0=1; i=0; P0=LedBuff[5]; break;
      default: break;
}
}

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