这个单片机程序能不能用蓝牙控制步进电机?求帮助 -

标题: 这个单片机程序能不能用蓝牙控制步进电机?求帮助 [打印本页]

作者: 尘封霜789 时间: 2019-7-7 00:23
标题: 这个单片机程序能不能用蓝牙控制步进电机?求帮助
//上电时电机启动，加减档位，电机采用单双八拍方式
//电机转速一共10档，通过按键调节转速
#include<reg51.h>
#include <intrins.h>
#include <math.h>
#define uchar unsigned char
#define uint unsigned int
uchar receive=0;
uchar send=0xff;
sbit out1=P3^0;
sbit out2=P3^1;
sbit out3=P3^2;
sbit s1 = P1^0;
sbit s2 = P1^1;
//按键定义,s1正转，s2反转，s3加1，s4减1
sbit a = P2^7;sbit b = P2^6;sbit c = P2^5;sbit d = P2^4;//脉冲信号输入端定义
uchar code time_counter[10][2]={{0xda,0x1c},{0xde,0xe4},{0xe1,0xec},{0xe5,0xd4},{0xe9,0xbc},  //9.7 ----1ms
                                                         {0xed,0xa4},{0xf1,0x8c},{0xf5,0x74},{0xf9,0x5c},{0xfc,0x18}};
uchar num1 = 0;//控制取励磁信号变量
uchar num2 = 8;

char k=0;//加减档位控制，1为最小档
char pause=1;//暂停时保存之前的转速，开机默认1
bit flag1 = 0;//初始正转，正反转标志
//================================定时器0/1初始化函数================================
void T0_T1_init()
{
      TMOD = 0x11;//定时器0/1均工作于方式1,16位计时方式
         TH1 = time_counter[k-1][0];
      TL1 = time_counter[k-1][1];//定时器1，定时10ms用于步进电机转速控制
      TR1 = 0;
      ET1= 1;//开定时器中断
      EA = 1;//开总中断
}
//================================ms级延时函数=======================================
void delay1m(uint x)
{
uint i,j;
for(i=0;i<x;i++)    //连数x次，约 x ms
         for(j=0;j<120;j++); //数120 次，约1 ms
}
void Com_Init(void)
{
   TMOD = 0x20;
   PCON = 0x00;
   SCON = 0x50;
   TH1 = 0xfd; //设置波特率 9600
   TL1 = 0xfd;
   TR1 = 1;             //启动定时器1
      ES = 1;             //开串口中断
      EA = 1;             //开总中断
}
//开关操作函数，接收到一次数据改变一次状态

void alloff()
{
      P1=0xff;

}
void Delay_1ms(uint i)//1ms延时
{
      uchar x,j;
      for(j=0;j<i;j++)
      for(x=0;x<=148;x++);
}
//================================主函数=============================================
void main()
{
      Delay_1ms(100);
      Com_Init();//串口初始化
  while (1)
      {
            T0_T1_init();
      a=b=c=d=0;
      while(1)
      {
            if(s1 == 0)
            {
                     delay1m(3);
                     if(s1 == 0)
                     {
                              flag1 = 0;//正转
                     }
                     while(!s1);
            }
            if(s2 == 0 )
            {

                     delay1m(3);
                     if(s2 == 0)
                     {
                              flag1 = 1;//反转
                     }
                     while(!s2);
            }
            if(out1 == 0)          //速度加1档
            {
                     delay1m(3);
                     if(out1 == 0)
                     {
                              k++;
                              TR1=1;
                              if(k > 10 )
                              {
                                    k = 1;
                              }
                     }
                     while(!out1);
            }
            if(out2 == 0)       //速度减1档
            {
                     delay1m(3);
                     if(out2 == 0)
                     {
                              k--;
                              TR1=1;
                              if(k <= 0)
                              {
                                    k = 10;
                              }
                     }
                     while(!out2);
            }
            if(out3==0)
            {
                     delay1m(3);
                     if(out3==0)
                     {
                              if(TR1==1)
                              {
                                    pause=k;
                                    k=0;
                                    TR1=0;
                                    a=b=c=d=0;
                              }
                              else if(TR1==0)
                              {
                                    k=pause;
                                    TR1=1;
                              }
                              while(!out3);
                     }
            }
      }
      }
}

void Com_Int(void) interrupt 4
{

      EA = 0;
      if(RI == 1) //当硬件接收到一个数据时，RI会置位
      {
            receive = SBUF ; //
            RI = 0;
            switch (receive)
            {
                     case 0x00: alloff();break;
                     case 0x10: out1=1;break;
                     case 0x11: out1=0;break;
                     case 0x20: out2=1;break;
                     case 0x21: out2=0;break;
                     case 0x30: out3=1;break;
                     case 0x31: out3=0;break;
                     default:break;
            }

      }
      EA = 1;
}
//==================================定时器1中断函数，用于脉冲频率控制=====================================
void time1_interrupt()interrupt 3
{
      static num1 = 0;
      static num2 = 0;
      TH1 = time_counter[k-1][0];
      TL1 = time_counter[k-1][1];//定时器1，定时1 用于步进电机转速控制
      if(flag1 == 0)//正转
      {
            switch(num1)
            {
                     case 0:a = 1;b = 0;c = 0;d = 0;break;
                     case 1:a = 1;b = 1;c = 0;d = 0;break;
                     case 2:a = 0;b = 1;c = 0;d = 0;break;
                     case 3:a = 0;b = 1;c = 1;d = 0;break;
                     case 4:a = 0;b = 0;c = 1;d = 0;break;
                     case 5:a = 0;b = 0;c = 1;d = 1;break;
                     case 6:a = 0;b = 0;c = 0;d = 1;break;
                     case 7:a = 1;b = 0;c = 0;d = 1;break;
            }
            num1++;
            if(num1 == 8)num1 = 0;
      }
      else                //反转
      {
            switch(num2)
            {
                     case 0:a = 1;b = 0;c = 0;d = 1;break;
                     case 1:a = 0;b = 0;c = 0;d = 1;break;
                     case 2:a = 0;b = 0;c = 1;d = 1;break;
                     case 3:a = 0;b = 0;c = 1;d = 0;break;
                     case 4:a = 0;b = 1;c = 1;d = 0;break;
                     case 5:a = 0;b = 1;c = 0;d = 0;break;
                     case 6:a = 1;b = 1;c = 0;d = 0;break;
                     case 7:a = 1;b = 0;c = 0;d = 0;break;
            }
            num2++;
            if(num2 == 8)num2 = 0;
      }
}
s1,s2两个按键不知道能不能用,求大神帮帮忙帮我看看。

作者: 卢森 时间: 2019-7-9 10:55
s1，s2是怎么产生的中断

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