实操Arduino+3d打印制造视觉暂留显示器附源程序 -

标题: 实操Arduino+3d打印制造视觉暂留显示器附源程序 [打印本页]

作者: 末世之王 时间: 2019-9-19 04:58
标题: 实操Arduino+3d打印制造视觉暂留显示器附源程序
制作出来的实物图如下：

配件清单
Arduino Nano×1
红外线传感器×1
洞洞板×1
LED 灯×若干
电阻×若干
直流电机×1
电池×1
电线×若干
热熔胶×1
烙铁×1
白纸×1
Arduino IDE（软件）

LED接口方式如下：
LED0：Nano 的 D2 。
LED1： Nano 的 D3 。
LED2： Nano 的 D4 。
LED3： Nano 的 D5 。
LED4： Nano 的 D6 。
LED5： Nano 的 D7 。
LED6： Nano 的 D8 。
LED7： Nano 的 D9 。
负极为：Nano 的 Ground 。

红外线传感器与 Nano 连接方式如下 :
GND：Nano 的 GND。
Vin： Nano 的 5V。
Out：Nano 的 D10。

代码
/*
* This Code demonstrates
* LED POV DISPLAY
*
* Components used
* 1) Arduino Nano
* 2) DC motor
* 3) LEDs
* 4) IR sensor
* 5) Battery
* 6) Wire
*
* Connect leds to 2 to 9 digital pin of Nano
* Connect IR sensor out pin to 10 digital pin of Nano
*
* code written by Palak Mehta on March 29,2019
*/
////////////////////////design a pattern of display the number and alphabates////////////////////////////////

int NUMBER9[]={1,1,1,1,0,0,0,1, 1,0,0,1,0,0,0,1, 1,0,0,1,0,0,0,1, 1,0,0,1,0,0,0,1, 1,1,1,1,1,1,1,1};
int NUMBER8[]={0,1,1,0,1,1,1,0, 1,0,0,1,0,0,0,1, 1,0,0,1,0,0,0,1, 1,0,0,1,0,0,0,1, 0,1,1,0,1,1,1,0};
int NUMBER7[]={1,0,0,0,0,0,0,0, 1,0,0,0,1,0,0,0, 1,0,0,0,1,0,0,0, 1,0,0,1,1,1,1,1, 1,1,1,0,1,0,0,0};
int NUMBER6[]={1,1,1,1,1,1,1,1, 1,0,0,0,1,0,0,1, 1,0,0,0,1,0,0,1, 1,0,0,0,1,0,0,1, 1,0,0,0,1,1,1,1};
int NUMBER5[]={1,1,1,1,1,0,0,1, 1,0,0,0,1,0,0,1, 1,0,0,0,1,0,0,1, 1,0,0,0,1,0,0,1, 1,0,0,0,1,1,1,1};
int NUMBER2[]= {1,0,0,0,0,0,1,1, 1,0,0,0,0,1,0,1, 1,0,0,0,1,0,0,1, 1,0,0,1,0,0,0,1, 0,1,1,0,0,0,0,1};
int NUMBER1[]= {0,0,1,0,0,0,0,0, 0,1,0,0,0,0,0,0, 1,1,1,1,1,1,1,1, 0,0,0,0,0,0,0,0, 0,0,0,0,0,0,0,0};
int NUMBER0[]= {1,1,1,1,1,1,1,1, 1,0,0,0,0,0,0,1, 1,0,0,0,0,0,0,1, 1,0,0,0,0,0,0,1, 1,1,1,1,1,1,1,1};

int _[] = {0,0,0,0,0,0,0,0, 0,0,0,0,0,0,0,0, 0,0,0,0,0,0,0,0, 0,0,0,0,0,0,0,0, 0,0,0,0,0,0,0,0};
int A[] = {1,1,1,1,1,1,1,1, 1,0,0,1,0,0,0,0, 1,0,0,1,0,0,0,0, 1,0,0,1,0,0,0,0, 1,1,1,1,1,1,1,1};
int B[] = {1,1,1,1,1,1,1,1, 1,0,0,1,0,0,0,1, 1,0,0,1,0,0,0,1, 1,0,0,1,0,0,0,1, 0,1,1,0,1,1,1,0};
int C[] = {0,0,1,1,1,1,0,0, 0,1,0,0,0,0,1,0, 1,0,0,0,0,0,0,1, 1,0,0,0,0,0,0,1, 1,0,0,0,0,0,0,1};
int D[] = {1,1,1,1,1,1,1,1, 1,0,0,0,0,0,0,1, 1,0,0,0,0,0,0,1, 0,1,0,0,0,0,1,0, 0,0,1,1,1,1,0,0};
int E[] = {1,1,1,1,1,1,1,1, 1,0,0,1,0,0,0,1, 1,0,0,1,0,0,0,1, 1,0,0,1,0,0,0,1, 1,0,0,1,0,0,0,1};
int F[] = {1,1,1,1,1,1,1,1, 1,0,0,1,0,0,0,0, 1,0,0,1,0,0,0,0, 1,0,0,1,0,0,0,0, 1,0,0,1,0,0,0,0};
int G[] = {0,1,1,1,1,1,1,1, 1,0,0,0,0,0,0,1, 1,0,0,0,1,0,0,1, 1,0,0,0,1,0,0,1, 1,0,0,0,1,1,1,0};
int H[] = {1,1,1,1,1,1,1,1, 0,0,0,0,1,0,0,0, 0,0,0,0,1,0,0,0, 0,0,0,0,1,0,0,0, 1,1,1,1,1,1,1,1};
int I[] = {1,0,0,0,0,0,0,1, 1,0,0,0,0,0,0,1, 1,1,1,1,1,1,1,1, 1,0,0,0,0,0,0,1, 1,0,0,0,0,0,0,1};
int J[] = {0,0,0,0,0,1,1,0, 0,0,0,0,1,0,0,1, 0,0,0,0,0,0,0,1, 0,0,0,0,0,0,0,1, 1,1,1,1,1,1,1,0};
int K[] = {1,1,1,1,1,1,1,1, 0,0,0,1,1,0,0,0, 0,0,1,0,0,1,0,0, 0,1,0,0,0,0,1,0, 1,0,0,0,0,0,0,1};
int L[] = {1,1,1,1,1,1,1,1, 0,0,0,0,0,0,0,1, 0,0,0,0,0,0,0,1, 0,0,0,0,0,0,0,1, 0,0,0,0,0,0,0,1};
int M[] = {1,1,1,1,1,1,1,1, 0,1,0,0,0,0,0,0, 0,0,1,0,0,0,0,0, 0,1,0,0,0,0,0,0, 1,1,1,1,1,1,1,1};
int N[] = {1,1,1,1,1,1,1,1, 0,0,1,0,0,0,0,0, 0,0,0,1,1,0,0,0, 0,0,0,0,0,1,0,0, 1,1,1,1,1,1,1,1};
int O[] = {0,1,1,1,1,1,1,0, 1,0,0,0,0,0,0,1, 1,0,0,0,0,0,0,1, 1,0,0,0,0,0,0,1, 0,1,1,1,1,1,1,0};
int P[] = {1,1,1,1,1,1,1,1, 1,0,0,1,0,0,0,0, 1,0,0,1,0,0,0,0, 1,0,0,1,0,0,0,0, 0,1,1,0,0,0,0,0};
int Q[] = {0,1,1,1,1,1,1,0, 1,0,0,0,0,0,0,1, 1,0,0,0,0,1,0,1, 0,1,1,1,1,1,1,0, 0,0,0,0,0,0,0,1};
int R[] = {1,1,1,1,1,1,1,1, 1,0,0,1,1,0,0,0, 1,0,0,1,0,1,0,0, 1,0,0,1,0,0,1,0, 0,1,1,0,0,0,0,1};
int S[] = {0,1,1,1,0,0,0,1, 1,0,0,0,1,0,0,1, 1,0,0,0,1,0,0,1, 1,0,0,0,1,0,0,1, 1,0,0,0,1,1,1,0};
int T[] = {1,0,0,0,0,0,0,0, 1,0,0,0,0,0,0,0, 1,1,1,1,1,1,1,1, 1,0,0,0,0,0,0,0, 1,0,0,0,0,0,0,0};
int U[] = {1,1,1,1,1,1,1,0, 0,0,0,0,0,0,0,1, 0,0,0,0,0,0,0,1, 0,0,0,0,0,0,0,1, 1,1,1,1,1,1,1,0};
int V[] = {1,1,1,1,1,1,0,0, 0,0,0,0,0,0,1,0, 0,0,0,0,0,0,0,1, 0,0,0,0,0,0,1,0, 1,1,1,1,1,1,0,0};
int W[] = {1,1,1,1,1,1,1,1, 0,0,0,0,0,0,1,0, 0,0,0,0,0,1,0,0, 0,0,0,0,0,0,1,0, 1,1,1,1,1,1,1,1};
int X[] = {1,1,0,0,0,0,1,1, 0,0,1,0,0,1,0,0, 0,0,0,1,1,0,0,0, 0,0,1,0,0,1,0,0, 1,1,0,0,0,0,1,1};
int Y[] = {1,1,0,0,0,0,0,0, 0,0,1,0,0,0,0,0, 0,0,0,1,1,1,1,1, 0,0,1,0,0,0,0,0, 1,1,0,0,0,0,0,0};
int Z[] = {1,0,0,0,0,1,1,1, 1,0,0,0,1,0,0,1, 1,0,0,1,0,0,0,1, 1,0,1,0,0,0,0,1, 1,1,0,0,0,0,0,1};

int* alpha[]= {A,B,C,D,E,F,G,H,I,J,K,L,M,N};//,T,U,V,W,X,Y,Z};
int letterSpace;
int delayTime;

#define IR_pin 10

void setup()
{
Serial.begin(9600);
pinMode(IR_pin,INPUT);
for( int i = 2; i<10 ;i++ ) // setting the ports of the leds to OUTPUT
{
pinMode(i, OUTPUT);
}

letterSpace =4;// defining the space between the letters (ms)
delayTime =1;// defining the time dots appear (ms)
}

void printLetter(int letter[])
{
int y;
// printing the first y row of the letter
for (y=0; y<8; y++)
{
digitalWrite(y+2, letter[y]);
}
delay(delayTime);
// printing the second y row of the letter
for (y=0; y<8; y++)
{
digitalWrite(y+2, letter[y+8]);
}
delay(delayTime);
// printing the third y row of the letter
for (y=0; y<8; y++)
{
digitalWrite(y+2, letter[y+16]);
}
delay(delayTime);
for(y = 0; y<8; y++) {
digitalWrite(y+2, letter[y+24]);
}
delay(delayTime);
for(y = 0; y<8; y++) {
digitalWrite(y+2, letter[y+32]);
}
delay(delayTime);
// printing the space between the letters
for (y=0; y<8; y++)
{
digitalWrite(y+2, 0);
}
delay(letterSpace);
}

void loop()
{
if(digitalRead(IR_pin)==LOW)
{
printLetter (P);
printLetter (O);
printLetter (V);
printLetter (_);
printLetter (_);
printLetter (D);
printLetter (I);
printLetter (S);
printLetter (P);
printLetter (L);
printLetter (A);
printLetter (Y);
printLetter (_);

}

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