标题:
单片机矩阵键盘与数码管 按下数字没有变化 求帮助
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作者:
江户川不是柯南
时间:
2019-12-16 13:19
标题:
单片机矩阵键盘与数码管 按下数字没有变化 求帮助
按下16个矩阵键盘依次在数码管上显示1 16的平方。我按下键盘数字没有变化 求帮助
#include<reg52.h>
#define uint unsigned int
#define uchar unsigned char
sbit dula=P2^6;
sbit wela=P2^7;
sbit key1=P3^4;
uchar code table[]={
0x3f,0x06,0x5b,0x4f,
0x66,0x6d,0x7d,0x07,
0x7f,0x6f,0x77,0x7c,
0x39,0x5e,0x79,0x71,0};
uchar code tablewe[]={
0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xff};
uint num,num1;
void delay(uint z)
{
uint x,y;
for(x=z;x>0;x--)
for(y=110;y>0;y--);
}
uint keyscan();
void init();
void display(uchar,uchar,uchar);
void main()
{
init();
while(1)
{
num1=keyscan();
display(num1/100,num1%100/10,num1%10);
}
}
void init()
{
dula=1;
P0=0x00;
dula=0;
wela=1;
P0=0xc0;
wela=0;
}
void display(uchar a,uchar b,uchar c)
{
dula=1;
P0=table[a];
dula=0;
P0=0xff;
wela=1;
P0=0xfe;
wela=0;
delay(1);
dula=1;
P0=table
;
dula=0;
P0=0xff;
wela=1;
P0=0xfd;
wela=0;
delay(1);
dula=1;
P0=table[c];
dula=0;
P0=0xff;
wela=1;
P0=0xfb;
wela=0;
delay(1);
}
uint keyscan()
{
P3=0xfe;
P3=P3&0xf0;
while(P3!=0xf0)
{
delay(5);
P3=P3&0xf0;
while(P3!=0xf0)
{
switch(P3)
{
case 0xee:num=1;
break;
case 0xde:num=4;
break;
case 0xbe:num=9;
break;
case 0x7e:num=16;
break;
}
while(P3!=0xf0)
{
P3=P3&0xf0;
}
}
}
P3=0xfd;
P3=P3&0xf0;
while(P3!=0xf0)
{
delay(5);
P3=P3&0xf0;
while(P3!=0xf0)
{
switch(P3)
{
case 0xed:num=25;
break;
case 0xdd:num=36;
break;
case 0xbd:num=49;
break;
case 0x7d:num=64;
break;
}
while(P3!=0xf0)
{
P3=P3&0xf0;
}
}
}
P3=0xfb;
P3=P3&0xf0;
while(P3!=0xf0)
{
delay(5);
P3=P3&0xf0;
while(P3!=0xf0)
{
switch(P3)
{
case 0xeb:num=81;
break;
case 0xdb:num=100;
break;
case 0xbb:num=121;
break;
case 0x7b:num=144;
break;
}
while(P3!=0xf0)
{
P3=P3&0xf0;
}
}
}
P3=0xf7;
P3=P3&0xf0;
while(P3!=0xf0)
{
delay(5);
P3=P3&0xf0;
while(P3!=0xf0)
{
switch(P3)
{
case 0xe7:num=169;
break;
case 0xd7:num=196;
break;
case 0xb7:num=225;
break;
case 0x77:num=256;
break;
}
while(P3!=0xf0)
{
P3=P3&0xf0;
}
}
}
return num;
}
作者:
xianfajushi
时间:
2019-12-17 16:09
调整一下数码显示中的延时量,学习蛋骗鸡最要紧的是先做好人机交互部分,然后调试其他的,先送一个值如4去调试显示数码管是否成功显示数字。
作者:
yanguang123
时间:
2019-12-17 20:24
打开程序调试,一步步执行,看哪步错了
作者:
wulin
时间:
2019-12-17 21:11
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#include<reg52.h>
#define uint unsigned int
#define uchar unsigned char
sbit dula=P2^6;
sbit wela=P2^7;
uchar code table[]={
0x3f,0x06,0x5b,0x4f,
0x66,0x6d,0x7d,0x07,
0x7f,0x6f,0x77,0x7c,
0x39,0x5e,0x79,0x71,0};
uchar code tablewe[]={
0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xff};
uchar data dis_buf[6];//显示缓存
uint key;
void delay(uint z)
{
uint x,y;
for(x=z;x>0;x--)
for(y=110;y>0;y--);
}
void keyscan();
void display();
void main()
{
while(1)
{
keyscan();
dis_buf[0]=table[key/100];//分解数据
dis_buf[1]=table[key/10%10];
dis_buf[2]=table[key%10];
display();
delay(1);
}
}
void display()
{
static uchar i=0;
P0=0x00;//消隐
dula=1;
dula=0;
P0=tablewe[i];//送位码
wela=1;
wela=0;
P0=dis_buf[i];//送段码
dula=1;
dula=0;
i++;
i%=3;
}
void keyscan() //按键扫描程序
{
static bit sign=0; //按键自锁标志
static uint count=0; //消抖计数变量
uchar num=0; //临时变量
P3=0xf0; //赋值P3 1111 0000
if(P3!=0xf0) //检测有按键按下
{
count++; //消抖计数
if((count>=10)&&(sign==0))
{
sign=1; //按键自锁标志置1
num=P3; //保存P3值xxxx 0000,x为0或1
num|=0x0f; //保存num按位或0x0f值xxxx 1111
P3=num; //赋值P3 xxxx 1111
num=P3; //读取并保存P3值xxxx xxxx
switch(num)
{
case 0xee: key= 1; break;
case 0xde: key= 4; break;
case 0xbe: key= 9; break;
case 0x7e: key= 16; break;
case 0xed: key= 25; break;
case 0xdd: key= 36; break;
case 0xbd: key= 49; break;
case 0x7d: key= 64; break;
case 0xeb: key= 81; break;
case 0xdb: key=100; break;
case 0xbb: key=121; break;
case 0x7b: key=144; break;
case 0xe7: key=169; break;
case 0xd7: key=196; break;
case 0xb7: key=225; break;
case 0x77: key=256; break;
}
}
}
else //键抬起
{
sign=0; //按键自锁标志清0
count=0; //消抖计数清0
}
}
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