单片机交通灯实验中添加LED屏幕后失效 -

标题: 单片机交通灯实验中添加LED屏幕后失效 [打印本页]

作者: azure1986 时间: 2020-4-7 11:07
标题: 单片机交通灯实验中添加LED屏幕后失效
原代码，能实现动态数码管和LED交通灯的动态显示。
为增加LED显示停和行，增加了LED代码模块，但增加后数码管和LED交通灯均不亮，LED乱码
请问是哪里出问题了。
运行结果正常。

修改后代码，红色部分，程序无报错，但数码管和LED灯都不亮，LED点阵乱码
#include "reg52.h"
#include "intrins.h"
typedef unsigned int u16;
typedef unsigned char u8;
#define led P0
#define light P1
sbit LSA=P2^2;
sbit LSB=P2^3;
sbit LSC=P2^4;
sbit GREEN00=P0^0;
sbit RED00=P0^1;
sbit GREEN10=P0^2;
sbit YELLOW10=P0^3;
sbit RED10=P0^4;
sbit GREEN11=P0^5;
sbit YELLOW11=P0^6;
sbit RED11=P0^7;
sbit GREEN01=P3^0;
sbit RED01=P3^1;
sbit SER=P2^7;
sbit SRCLK=P2^6;
sbit RCLK1=P2^5;
u8 code smg[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,
0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71};

u8 code duan2[]={0x80,0x60,0xF8,0x07,0x00,0x04,0x74,0x54,0x55,0x56,0x54,0x54,0x74,0x04,0x00,0x00,
0x00,0x00,0xFF,0x00,0x03,0x01,0x05,0x45,0x85,0x7D,0x05,0x05,0x05,0x01,0x03,0x00,};       //?
u8 code duan1[]={0x00,0x10,0x88,0xC4,0x33,0x00,0x40,0x42,0x42,0x42,0xC2,0x42,0x42,0x42,0x40,0x00,
0x02,0x01,0x00,0xFF,0x00,0x00,0x00,0x00,0x40,0x80,0x7F,0x00,0x00,0x00,0x00,0x00,};       //??
u8 code wei[32]={0x01,0x02,0x04,0x08,0x10,0x20,0x40,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x02,0x04,0x08,0x10,0x20,0x40,0x80,};

u8 Second=0;
u8 DisplayData[8];

void delay(u16 t);
void inter0();
void Display();

void LEDDZ(u8 dat1,u8 dat2,u8 dat3,u8 dat4);
void DZdisplay1();
void DZdisplay2();

void LEDDZ(u8 dat1,u8 dat2,u8 dat3,u8 dat4)
{ u8 a;
  for(a=0;a<8;a++)
  { SER=dat1>>7;
dat1=dat1<<1;
SRCLK=0;
_nop_();
SRCLK=1;
}
  for(a=0;a<8;a++)
  { SER=dat2>>7;
dat2=dat2<<1;
SRCLK=0;
_nop_();
SRCLK=1;
}
  for(a=0;a<8;a++)
  { SER=dat3>>7;
dat3=dat3<<1;
SRCLK=0;
_nop_();
SRCLK=1;
}
  for(a=0;a<8;a++)
  { SER=dat4>>7;
dat4=dat4<<1;
SRCLK=0;
_nop_();
SRCLK=1;
}
  RCLK1=0;
  _nop_();
  RCLK1=1;
  }

void DZdisplay1()
{ u8 i;
while(1)
{ for(i=0;i<16;i++)
   {LEDDZ(~wei[i+16],~wei[ i],duan1[i+16],duan1[ i]);
delay(10);}
   }
  }

void DZdisplay2()
{ u8 i;
while(1)
{ for(i=0;i<16;i++)
   {LEDDZ(~wei[i+16],~wei[ i],duan2[i+16],duan2[ i])；
delay(10);}
   }
  }[ i][ i][ i]

void delay(u16 t)
{while(t--);}
void inter0()
{TMOD=0X01;
  TH0=0XFC;
  TL0=0X18;
  EA=1;
  ET0=1;
  TR0=1;
  }
void Display()
{ u8 i;
light=0x00;
for(i=0;i<8;i++)
{ switch(i)
   {case(0):LSA=0;LSB=0;LSC=0;break;
case(1):LSA=1;LSB=0;LSC=0;break;
case(2):LSA=0;LSB=1;LSC=0;break;
case(3):LSA=1;LSB=1;LSC=0;break;
case(4):LSA=0;LSB=0;LSC=1;break;
case(5):LSA=1;LSB=0;LSC=1;break;
case(6):LSA=0;LSB=1;LSC=1;break;
case(7):LSA=1;LSB=1;LSC=1;break;
}
  light=DisplayData[ i];
  delay(100);
  light=0x00;
  }
  }

void main()
{ inter0();
while(1)
{if(Second==70)
   {
Second=0;
}
if(Second<31)
  {
DisplayData[0]=0x00;
DisplayData[1]=0x00;
DisplayData[2]=smg[(30-Second)%100/10];
DisplayData[3]=smg[(30-Second)%10];
DisplayData[4]=0x00;
DisplayData[5]=0x00;
DisplayData[6]=DisplayData[2];
DisplayData[7]=DisplayData[3];
Display();
DZdisplay2()；
led=0xff;
GREEN01=1;
RED01=1;
GREEN00=0;
GREEN10=0;
RED11=0;
RED01=0;
}
else if(Second<36)
  {
DisplayData[0]=0x00;
DisplayData[1]=0x00;
DisplayData[2]=smg[(36-Second)%100/10];
DisplayData[3]=smg[(36-Second)%10];
DisplayData[4]=0x00;
DisplayData[5]=0x00;
DisplayData[6]=DisplayData[2];
DisplayData[7]=DisplayData[3];
Display();
led=0xff;
GREEN01=1;
RED01=1;
RED00=0;
YELLOW10=0;
RED11=0;
RED01=0;
}
else if(Second<66)
  {
DisplayData[0]=0x00;
DisplayData[1]=0x00;
DisplayData[2]=smg[(66-Second)%100/10];
DisplayData[3]=smg[(66-Second)%10];
DisplayData[4]=0x00;
DisplayData[5]=0x00;
DisplayData[6]=DisplayData[2];
DisplayData[7]=DisplayData[3];
Display();
DZdisplay1()；
led=0xff;
GREEN01=1;
RED01=1;
RED00=0;
RED10=0;
GREEN11=0;
GREEN01=0;
}
else
  {
DisplayData[0]=0x00;
DisplayData[1]=0x00;
DisplayData[2]=smg[(71-Second)%100/10];
DisplayData[3]=smg[(71-Second)%10];
DisplayData[4]=0x00;
DisplayData[5]=0x00;
DisplayData[6]=DisplayData[2];
DisplayData[7]=DisplayData[3];
Display();
led=0xff;
GREEN01=1;
RED01=1;
RED00=0;
RED10=0;
YELLOW11=0;
RED01=0;
}
}
}
void inter0in() interrupt 1
{ static u16 i;
TH0=0XFC;
TL0=0X18;
i++;
if(i==1000)
{i=0;
Second++;
}
}

作者: man1234567 时间: 2020-4-10 22:16
你查一下实验板的电路图，极有可能是I/O口占用。

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