16x32点阵显示2个汉字的proteus仿真电路及单片机C语言程序 -

标题: 16x32点阵显示2个汉字的proteus仿真电路及单片机C语言程序 [打印本页]

作者: sok 时间: 2020-6-9 23:34
标题: 16x32点阵显示2个汉字的proteus仿真电路及单片机C语言程序

#include <REGX52.H>

sbit SCLK=P1^0;
sbit DAT=P1^2;
sbit SLCK=P1^1;
sbit P20=P2^0;
sbit P21=P2^1;
sbit P22=P2^2;
sbit P23=P2^3;

#define uchar unsigned char
#define uint unsigned int
uchar code table[64]={//{0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
//0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00},
0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x04,0xFF,0xFE,0x01,0x00,0x02,0x80,
0x02,0x80,0x02,0x40,0x04,0x40,0x04,0x20,0x08,0x10,0x10,0x0E,0x60,0x04,0x00,0x00};// 大
//0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
//0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00},
uchar code table1[64]={
0x22,0x08,0x11,0x08,0x11,0x10,0x00,0x20,0x7F,0xFE,0x40,0x02,0x80,0x04,0x1F,0xE0,
0x00,0x40,0x01,0x84,0xFF,0xFE,0x01,0x00,0x01,0x00,0x01,0x00,0x05,0x00,0x02,0x00,//学

//{0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
// 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00}
};

void delay(void);

uint offset;

void display_595(uchar L1,uchar L2,uchar L3,uchar L4)//
{  uchar i;
uchar j;
  uchar a[3];

      a[0]=L1;
               a[1]=L2;
      a[2]=L3;
               a[3]=L4;

   SLCK=0;
for(j=0;j<4;j++)
  {
      for(i=0;i<8;i++)//把数组中的每一个数送到移位寄存器（8位的数）
      {
      SCLK=0;//寄存器的时钟输入，上升沿有效
      DAT=a[j]&0x80;
      a[j]=a[j]<<1; //将a值左移一位
      SCLK=1;
      }

}
SLCK=1;

}



void main(void)

{
TMOD=0x01;
TH0=0xb1;
TL0=0xe0;
ET0=1;
EA=1;
TR0=1;

while(1)
{  uchar i;
for(i=0;i<16;i++)
{
display_595(table[offset+2*i],table[offset+2*i+1],table1[offset+2*i],table1[offset+2*i+1]);//
delay();

P2=i;

  delay();

}
}
}
void delay(void)
{
uint i;

for(i=0;i<10;i++);
}

void timer0() interrupt 1 using 3
{
      uchar n;
      TF0=0;
      TH0=0xb1;
      TL0=0xe0;
      if(n<20)
      {
         n++;
      }
      else
      {

//  offset+=2;
//if(offset>32)
// offset=0;

         n=0;
      }

}

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16x32点阵显示2个汉字计.zip (48.19 KB, 下载次数: 31)

作者: songxia8013 时间: 2020-6-15 08:22
这仿真都没法用，怎么还分享出来？

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