标题:
51单片机8*8LED点阵翻页 闪烁 静止 平移显示(仿真+程序)有模式切换按钮
[打印本页]
作者:
高山
时间:
2020-6-11 15:41
标题:
51单片机8*8LED点阵翻页 闪烁 静止 平移显示(仿真+程序)有模式切换按钮
基于单片机的LED点阵设计
基本要求:利用单片机AT89C51设计LED点阵,显示器能显示不同的字符、图形,能够用独立键控制不同字符的切换效果。
创新:显示效果可以是闪烁;静止;平移等。
任务区分:A——每隔1s闪烁1次
B——循环平移,速度自定
仿真原理图如下(proteus仿真工程文件可到本帖附件中下载)
51hei.png
(40.51 KB, 下载次数: 52)
下载附件
2020-6-11 18:41 上传
单片机源程序如下:
#include <reg52.h>
sbit ADDR0 = P1^0;
sbit ADDR1 = P1^1;
sbit ADDR2 = P1^2;
sbit ADDR3 = P1^3;
sbit KEY = P3^5;
unsigned int cnt,m,stage,sec=1000;
unsigned char code image[][8] = {
{0xFF,0xE7,0xDB,0xDB,0xDB,0xDB,0xE7,0xFF}, //0
{0xFF,0xE7,0xEF,0xEF,0xEF,0xEF,0xC3,0xFF}, //1
{0xFF,0xE3,0xDF,0xDF,0xE7,0xFB,0xC3,0xFF}, //2
{0xE3,0xDF,0xDF,0xE7,0xDF,0xDF,0xE3,0xFF}, //3
{0xFF,0xEF,0xE7,0xEB,0xC3,0xEF,0xEF,0xFF}, //4
{0xFB,0xC3,0xFB,0xE3,0xDF,0xDF,0xE3,0xFF}, //5
{0xE7,0xFB,0xFB,0xE3,0xDB,0xDB,0xE7,0xFF}, //6
{0xFF,0xC3,0xDF,0xDF,0xDF,0xDF,0xDF,0xFF}, //7
{0xE7,0xDB,0xDB,0xE7,0xDB,0xDB,0xE7,0xFF}, //8
{0xE7,0xDB,0xDB,0xC7,0xDF,0xDF,0xE7,0xFF} //9
};
unsigned char code image1[][8] = { //心跳
{0xFF,0x99,0x00,0x00,0x00,0x81,0xC3,0xE7}, //大心
{0xFF,0xFF,0xDB,0x81,0x81,0xC3,0xE7,0xFF}, //中心
{0xFF,0xFF,0xFF,0xDB,0xC3,0xE7,0xFF,0xFF}, //小心
};
unsigned char code image3[][8] = { //小坦克
{0xFE,0xFF,0xE3,0xE3,0xF7,0xFF,0xFF,0xFF},
{0xFE,0xFF,0xFF,0xE3,0xE3,0xF7,0xFF,0xFF},
{0xFE,0xFF,0xFF,0xFF,0xE3,0xE3,0xF7,0xFF},
{0xFE,0xFF,0xFF,0xFF,0xF3,0xE3,0xF3,0xFF},
{0xFE,0xFF,0xFF,0xFF,0xE7,0xC7,0xE7,0xFF},
{0xFE,0xFF,0xFF,0xFF,0xCF,0x8F,0xCF,0xFF},
{0xFE,0xFF,0xFF,0xFF,0xDF,0x8F,0x8F,0xFF},
{0xFE,0xFF,0xFF,0xDF,0x8F,0x8F,0xFF,0xFF},
{0xFE,0xFF,0xDF,0x8F,0x8F,0xFF,0xFF,0xFF},
{0xFE,0xDF,0x8F,0x8F,0xFF,0xFF,0xFF,0xFF},
};
unsigned char code image2[] = { //0-->9平移
0xFF,0xE7,0xDB,0x5A,0x5A,0xDB,0xE7,0xFF,0xFF,0xE7,0xEF,0x6E,0x6E,0xEF,0xC3,0xFF,
0xFF,0xE3,0xDF,0x5E,0x66,0xFB,0xC3,0xFF,0xE3,0xDF,0xDF,0x66,0x5E,0xDF,0xE3,0xFF,
0xFF,0xEF,0xE7,0x6A,0x42,0xEF,0xEF,0xFF,0xFB,0xC3,0xFB,0x62,0x5E,0xDF,0xE3,0xFF,
0xE7,0xFB,0xFB,0x62,0x5A,0xDB,0xE7,0xFF,0xFF,0xC3,0xDF,0x5E,0x5E,0xDF,0xDF,0xFF,
0xE7,0xDB,0xDB,0x66,0x5A,0xDB,0xE7,0xFF,0xE7,0xDB,0xDB,0x46,0x5E,0xDF,0xE7,0xFF,
};
void Delay10ms()
{
unsigned char i, j;
i = 20;
j = 113;
do
{
while (--j);
} while (--i);
}
void main()
{
EA = 1; //使能总中断
ADDR3 = 0;
TMOD = 0x01; //设置T0为模式1
TH0 = 0xFC; //为T0赋初值0xFC67,定时1ms
TL0 = 0x67;
ET0 = 1; //使能T0中断
TR0 = 1; //启动T0
while (1)
{
if(stage>3)stage=0;
if(KEY==0)
{
Delay10ms();
if(KEY==1)stage++;
}
if(cnt >= sec)
{
cnt = 0;
m++;
}
}
}
/* 定时器0中断服务函数 */
void InterruptTimer0() interrupt 1
{
static unsigned char i = 0; //动态扫描的索引
static unsigned char tmr = 0; //250ms软件定时器
static unsigned char index = 0; //图片刷新索引
TH0 = 0xFC; //重新加载初值
TL0 = 0x67;
P0 = 0xFF; //显示消隐
cnt++;
/***********************模式一:数字闪出***********************************/
if(stage==0)
{
sec = 1000;
if(m>=10)m=0;
switch (i)
{
case 0: ADDR2=0; ADDR1=0; ADDR0=0; i++; P0=image[m][0]; break;
case 1: ADDR2=0; ADDR1=0; ADDR0=1; i++; P0=image[m][1]; break;
case 2: ADDR2=0; ADDR1=1; ADDR0=0; i++; P0=image[m][2]; break;
case 3: ADDR2=0; ADDR1=1; ADDR0=1; i++; P0=image[m][3]; break;
case 4: ADDR2=1; ADDR1=0; ADDR0=0; i++; P0=image[m][4]; break;
case 5: ADDR2=1; ADDR1=0; ADDR0=1; i++; P0=image[m][5]; break;
case 6: ADDR2=1; ADDR1=1; ADDR0=0; i++; P0=image[m][6]; break;
case 7: ADDR2=1; ADDR1=1; ADDR0=1; i=0; P0=image[m][7]; break;
default: break;
}
}
/**********************模式二:动态爱心************************************/
else if(stage==1)
{
sec = 150;
if(m>=3)m=0;
switch (i)
{
case 0: ADDR2=0; ADDR1=0; ADDR0=0; i++; P0=image1[m][0]; break;
case 1: ADDR2=0; ADDR1=0; ADDR0=1; i++; P0=image1[m][1]; break;
case 2: ADDR2=0; ADDR1=1; ADDR0=0; i++; P0=image1[m][2]; break;
case 3: ADDR2=0; ADDR1=1; ADDR0=1; i++; P0=image1[m][3]; break;
case 4: ADDR2=1; ADDR1=0; ADDR0=0; i++; P0=image1[m][4]; break;
case 5: ADDR2=1; ADDR1=0; ADDR0=1; i++; P0=image1[m][5]; break;
case 6: ADDR2=1; ADDR1=1; ADDR0=0; i++; P0=image1[m][6]; break;
case 7: ADDR2=1; ADDR1=1; ADDR0=1; i=0; P0=image1[m][7]; break;
default: break;
}
}
/**********************模式三:坦克走动**************************************/
else if(stage==2)
{
sec = 800;
if(m>=10)m=0;
switch (i)
{
case 0: ADDR2=0; ADDR1=0; ADDR0=0; i++; P0=image3[m][0]; break;
case 1: ADDR2=0; ADDR1=0; ADDR0=1; i++; P0=image3[m][1]; break;
case 2: ADDR2=0; ADDR1=1; ADDR0=0; i++; P0=image3[m][2]; break;
case 3: ADDR2=0; ADDR1=1; ADDR0=1; i++; P0=image3[m][3]; break;
case 4: ADDR2=1; ADDR1=0; ADDR0=0; i++; P0=image3[m][4]; break;
case 5: ADDR2=1; ADDR1=0; ADDR0=1; i++; P0=image3[m][5]; break;
case 6: ADDR2=1; ADDR1=1; ADDR0=0; i++; P0=image3[m][6]; break;
case 7: ADDR2=1; ADDR1=1; ADDR0=1; i=0; P0=image3[m][7]; break;
default: break;
}
}
/**********************模式四:数字平移****************************************/
else if(stage==3)
{
switch (i)
{
case 0: ADDR2=0; ADDR1=0; ADDR0=0; i++; P0=image2[index+0]; break;
case 1: ADDR2=0; ADDR1=0; ADDR0=1; i++; P0=image2[index+1]; break;
case 2: ADDR2=0; ADDR1=1; ADDR0=0; i++; P0=image2[index+2]; break;
case 3: ADDR2=0; ADDR1=1; ADDR0=1; i++; P0=image2[index+3]; break;
case 4: ADDR2=1; ADDR1=0; ADDR0=0; i++; P0=image2[index+4]; break;
case 5: ADDR2=1; ADDR1=0; ADDR0=1; i++; P0=image2[index+5]; break;
case 6: ADDR2=1; ADDR1=1; ADDR0=0; i++; P0=image2[index+6]; break;
case 7: ADDR2=1; ADDR1=1; ADDR0=1; i=0; P0=image2[index+7]; break;
default: break;
}
//以下代码完成每250ms改变一帧图像
tmr++;
if (tmr >= 250) //达到250ms时改变一次图片索引
{
tmr = 0;
index++;
if (index >= 72) //图片索引达到32后归零
{
index = 0;
}
}
}
}
复制代码
所有资料51hei提供下载:
点阵显示.zip
(112.3 KB, 下载次数: 155)
2020-6-11 15:40 上传
点击文件名下载附件
下载积分: 黑币 -5
作者:
黑天科技
时间:
2020-6-27 21:51
楼主电路图好像不全哦
作者:
hhdsdy
时间:
2020-12-3 21:53
自己写的一个翻页感觉不是满意,下载一个参考一下思路,谢谢了!
作者:
电子电子小宅神
时间:
2021-10-23 15:50
取模格式是咋样的吖
欢迎光临 (http://www.51hei.com/bbs/)
Powered by Discuz! X3.1