大神帮我看一下我的程序,我是初学者谢谢 -

标题: 大神帮我看一下我的程序,我是初学者谢谢 [打印本页]

作者: jkl8687 时间: 2014-11-10 22:21
标题: 大神帮我看一下我的程序,我是初学者谢谢
/*这是用外部中断下降沿第1次在3秒内达5次以上点亮Green_LED 和 LED5 ,如果少以5次Red_LED程序停止 . 第2.3次依次 */
#include <reg52.h>
#define uchar unsigned char
#define uint unsigned int
uchar counter1;
uchar JDQ1,JDQ2,JDQ3;
sbit Green_LED =P0^0;
sbit Green_LED1 =P0^1;
sbit Green_LED2 =P0^2;
sbit Red_LED =P0^3;
sbit LED5 =P1^0;
sbit LED6 =P1^1;
sbit LED7 =P1^2;
sbit LED8 =P1^3;
void Delay_1ms(unsigned int Time)
{
  unsigned int x, y;
  for(x = Time; x > 0; x--)
for(y = 120; y > 0; y--);
}
void timer1_init()
{
   TMOD |= 0x10;
   TMOD &= 0xdf;
   TH0 = (65536-50000)/256;
   TL0 = (65536-50000)%256;
   TR0 = 1; //启动定时器0
  TF0=0;
}
void interrupter_init()
{
ET0 = 1; //开定时器0中断

EX0=1; //开外部中断0
EA=1;  //开总中断
IT0=1; //下降沿触发
//IE0=0;
PX0=1;
// TCON |=0X01;
}
main()
{
   timer1_init();
   interrupter_init();
  Red_LED =1;
   Green_LED =1;
   Green_LED1 = 1;
   Green_LED2 =1;
  LED5  = 1;
  LED6  = 1;
  LED7  = 1;
  LED8  = 1;
  JDQ1=0;
  JDQ2=0;
  JDQ3=0;
   while(1);
}
void ISR_Key(void) interrupt 0
{
counter1++;
  }
void interrupt_timer1() interrupt 1
{
   uint sec;
   uchar counter;
TF0=0;
   TH0 = (65536-50000)/256;
   TL0 = (65536-50000)%256;

   counter++;
   if(counter ==20)
   {
      counter = 0;
if(JDQ2==0)
      sec++;
         if ((sec<30)&&(counter1>=5))
   {
         Green_LED=0;
         LED5 =0;


   }
if ((sec<30)&&(counter1>=5)&&(JDQ1 ==1))
      { JDQ1=2;
         Green_LED1 =0;
         LED6 = 0;

         }

   if ((sec<30)&&(counter1>=5)&&(JDQ1 ==3))
      { JDQ1=4;
         Green_LED2 =0;
         LED7 = 0;

      }
if ((sec>=30)&&(counter1<5))
{
         Red_LED=0;
   }
      if (sec>=40)
{ sec=0;counter1=0;
         JDQ1=1;
if (JDQ2==2)
{
      JDQ1=3;
}
if(JDQ1==4)
{
   JDQ1=0;
   JDQ2=1;
   LED8  =0;

}
}
   }

}

作者: jkl8687 时间: 2014-11-10 23:58
大神快帮帮忙

作者: mqwu 时间: 2014-11-11 09:03
这个代码2个星期前我帮另一个人写过，请在帖子里找一下

作者: jkl8687 时间: 2014-11-11 09:14
找不到

作者: jkl8687 时间: 2014-11-11 09:52
看一下我的错在哪里

作者: mqwu 时间: 2014-11-11 11:25
//用一个外部中断做按5次的键，一个定时器来判断3秒溢出，如果定时器在3秒内按了5次，外部中断重新赋初值，这样防止定时器在3秒溢出，绿灯亮。反之，定时器溢出将使得红灯亮，用12M crystal 和数码管+38译码器

#include <reg52.h>
#define uchar unsigned char
#define uint unsigned int

code uchar number[] = {0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90};

uchar a[6];

sbit ENLED = P1^4;
sbit ADDR0 = P1^0;
sbit ADDR1 = P1^1;
sbit ADDR2 = P1^2;
sbit ADDR3 = P1^3;
sbit Green_LED =P2^0;
sbit Red_LED =P2^1;

void timer1_init()
{
TMOD |= 0x10;
TMOD &= 0xdf;
TH1 = 0x3C;
TL1 = 0xB0;
TR1 = 1;
}
void interrupter_init()
{
ET1 = 1;
EA=1;       //è«¾ÖÖD¶Ï¿a
EX0=1;       //ía2¿ÖD¶Ï0¿a
IT0=1;       //±ßÑØ′￥·￠
}
void Scanning_Numerical_LED(void)
{
   static uchar j = 0;
      switch(j)
   {
      case 0: ADDR0 = 0;ADDR1 = 0;ADDR2 = 0;j++;P0 = number[a[0]];break;
      case 1: ADDR0 = 1;ADDR1 = 0;ADDR2 = 0;j++;P0 = number[a[1]];break;
      case 2: ADDR0 = 0;ADDR1 = 1;ADDR2 = 0;j++;P0 = number[a[2]];break;
      case 3: ADDR0 = 1;ADDR1 = 1;ADDR2 = 0;j++;P0 = number[a[3]];break;
      case 4: ADDR0 = 0;ADDR1 = 0;ADDR2 = 1;j++;P0 = number[a[4]];break;
      case 5: ADDR0 = 1;ADDR1 = 0;ADDR2 = 1;j = 0;P0 = number[a[5]];break;
      default: break;
         }

}

main()
{
ENLED = 0; ADDR3 = 1;
timer1_init();
interrupter_init();
while(1)
{
   Scanning_Numerical_LED();
}

}

void ISR_Key(void) interrupt 0 using 1

{
  uchar counter1;
  counter1++;
  TR1=1;
  if (counter1==5)
{
   counter1=0;
   TH1 = 0x3C;  //50 ms setting;
   TL1 = 0xB0;
}

}

void interrupt_timer1() interrupt 3
{
   uint sec;
   uchar counter;
   TH1 = 0x3C;  //50 ms setting;
   TL1 = 0xB0;
   counter++;
   if(counter ==20)
   {
      counter = 0;
      sec++;
      if (sec>=3)
      {
         Red_LED=1;
         TR1=0; 停定时器1；
      }
      else Green_LED=1;
      if (sec==10)
         sec=0;

      a[0] = sec%10;
      a[1] = sec/10;
      //a[2] = sec/100%10;
   // a[3] = sec/1000%10;
      //a[4] = sec/10000%10;
   // a[5] = sec/100000%10;
   }

}

作者: jkl8687 时间: 2014-11-11 20:51
我这个程序要实现在3秒内外部中断沿进入5次以上同时用一个IO口接开关按下绿灯亮，如果不管哪一个不成立就红灯亮

作者: 明白 时间: 2014-11-11 21:03
用一个定时器就可以，不用外中断做按键。
这样按键可以用任意IO，
多少个按键都可以

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