单片机简易信号发生器问题求助 -

标题: 单片机简易信号发生器问题求助 [打印本页]

作者: xiaoxiaoxin 时间: 2016-1-12 13:24
标题: 单片机简易信号发生器问题求助
不知道哪里出错，仿真时没波形，求高手修改。或有更简单的代码和仿真图也可以发给我。要简单的！
#include<reg51.h>
#include<absacc.h>
#define P0 XBYTE[0xdf00] // P0琐存地址
unsigned char code
seg[]={0xC0,0xF9,0xA4,0xB0,0x99,0x92,0x82,0xF8,0x80,0x90}; //显示数组
unsigned char code sig_sin[256]={
0x80,0x83,0x86,0x89,0x8c,0x8f,0x92,0x95,0x98,0x9c,0x9f,0xa2,0xa5,0xa8,0xab,0xae,
0xb0,0xb3,0xb6,0xb9,0xbc,0xbf,0xc1,0xc4,0xc7,0xc9,0xcc,0xce,0xd1,0xd3,0xd5,0xd8,
0xda,0xdc,0xde,0xe0,0xe2,0xe4,0xe6,0xe8,0xea,0xec,0xed,0xef,0xf0,0xf2,0xf3,0xf4,
0xf6,0xf7,0xf8,0xf9,0xfa,0xfb,0xfc,0xfc,0xfd,0xfe,0xfe,0xff,0xff,0xff,0xff,0xff,
0xff,0xff,0xff,0xff,0xff,0xff,0xfe,0xfe,0xfd,0xfc,0xfc,0xfb,0xfa,0xf9,0xf8,0xf7,
0xf6,0xf5,0xf3,0xf2,0xf0,0xef,0xed,0xec,0xea,0xe8,0xe6,0xe4,0xe3,0xe1,0xde,0xdc,
0xda,0xd8,0xd6,0xd3,0xd1,0xce,0xcc,0xc9,0xc7,0xc4,0xc1,0xbf,0xbc,0xb9,0xb6,0xb4,
0xb1,0xae,0xab,0xa8,0xa5,0xa2,0x9f,0x9c,0x99,0x96,0x92,0x8f,0x8c,0x89,0x86,0x83,
0x80,0x7d,0x79,0x76,0x73,0x70,0x6d,0x6a,0x67,0x64,0x61,0x5e,0x5b,0x58,0x55,0x52,
0x4f,0x4c,0x49,0x46,0x43,0x41,0x3e,0x3b,0x39,0x36,0x33,0x31,0x2e,0x2c,0x2a,0x27,
0x25,0x23,0x21,0x1f,0x1d,0x1b,0x19,0x17,0x15,0x14,0x12,0x10,0xf,0xd,0xc,0xb,0x9,
0x8,0x7,0x6,0x5,0x4,0x3,0x3,0x2,0x1,0x1,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x0,0x0,
0x0,0x1,0x1,0x2,0x3,0x3,0x4,0x5,0x6,0x7,0x8,0x9,0xa,0xc,0xd,0xe,0x10,0x12,0x13,
0x15,0x17,0x18,0x1a,0x1c,0x1e,0x20,0x23,0x25,0x27,0x29,0x2c,0x2e,0x30,0x33,0x35,
0x38,0x3b,0x3d,0x40,0x43,0x46,0x48,0x4b,0x4e,0x51,0x54,0x57,0x5a,0x5d,0x60,0x63,
0x66,0x69,0x6c,0x6f,0x73,0x76,0x79,0x7c
};
unsigned char a; //全局信号信号选择变量
unsigned int b; //全局信号档位变量送显示
unsigned int pinlv; // 档位变量送定时器赋初值
unsigned int i=0; // 中断服务计数
sbit butten_swtich=P3^2; //按键1 波形选择
sbit butten_up =P3^3; //按键2 频率+
sbit butten_down =P3^4; //按键3 频率-
void delay1ms(unsigned char ii)//延时基时1毫秒子程序
{
unsigned char jj;
for(;ii>0;ii--)
for(jj=0;jj<125;jj++);
}
void Init_Timer1(void) //定时器0初始化
{
EA=1; //开总中断
ET1=1; //定时器T1中断允许
TMOD=0x10; //TMOD=0001 000B，使用定时器T1的模式1
TH1=(65536-500)/256; //定时器T1的高8位赋初值
TL1=(65536-500)%256; //定时器T1的高8位赋初值
TR1=1; //启动定时器T1
}
void butten_scan1() //按键处理子程序
{
if(butten_swtich==0) //信号按键选择
{
delay1ms(20);//消抖延时
if(butten_swtich==0)
{
while(!butten_swtich); //等待按键松开
a++;
if(a>3)a=1; //循环选择
}
}
}
void butten_scan2()
{
if(butten_up==0) //信号按键选择
{
delay1ms(20); //消抖延时
if(butten_up==0)
{
while(!butten_up); //等待按键松开
b=b+1;
if(b>9)b=9; //再按加就不再加了
}
}
else if(butten_down==0) //信号按键选择
{
delay1ms(10);//消抖延时
if(butten_down==0)
{
while(!butten_down); //等待按键松开
b=b-1;
if(b<1)b=1; //再按减就不再减了
}
}
}
main()
{
a=1;b=5;
Init_Timer1();
while(1)
{
butten_scan1(); //调用按键处理子程序
butten_scan2();
P2=0x1;
P1=seg[a]; //信号输出送显示 1三角波 2正弦波 3方波
delay1ms(10);
P2=0x8;
P1=seg; //档位显示0~9 默认第5档
delay1ms(10);
}
}
void OS_Timer1(void) interrupt 3 // 系统OS定时中断服务
{
switch(b) //根据不同的档位给定时器赋不同的初值
{
case 1: pinlv=0xf2;break;
case 2: pinlv=0xf3;break;
case 3: pinlv=0xf4;break;
case 4: pinlv=0xf5;break;
case 5: pinlv=0xf6;break;
case 6: pinlv=0xf7;break;
case 7: pinlv=0xf8;break;
case 8: pinlv=0xf9;break;
case 9: pinlv=0xfa;break;
}
TH1=pinlv;  //定时器赋初值
TL1=0xff; //定时器赋初值
if (a==1) P0=sig_sin; //P0口给正弦波信号数组
else if (a==2) {if(i<128)P0=2*i;else P0=254-2*i;}//P0口给三角波信号数组
else if (a==3){ if(i>128)P0=0xff;else P0=0;} //方波
i++;if(i>255)i=0;
}

无标题.png (97.57 KB, 下载次数: 166)

仿真图

作者: fx123 时间: 2016-1-12 15:57
看不出来喔，不过帮忙顶

作者: 暗光 时间: 2016-1-12 23:51

2A-DAC0832-锯齿波（实验2）2014.10.24.zip (38.7 KB, 下载次数: 20) 这有一个我原来做过的实验，没用中断，没有按键，我看了你的，问题可能在于你的中断函数中送波形你直接把数组地址给传出去了，却没有让数组地址++，很可能只发送了一个数据，建议在中断中把起始地址给更改了，在主循环中把数组内容一个一个送给DAC

作者: 黑子斑 时间: 2016-6-22 17:36

暗光发表于 2016-1-12 23:51
这有一个我原来做过的实验，没用中断，没有按键，我看了你的，问题可能在于你的中断函数中送波形你直接把 ...

不全。

作者: 暗光 时间: 2016-6-23 13:42

黑子斑发表于 2016-6-22 17:36
不全。

是的，这个只是一个实验，不是信号发生器全部信号，不过原理差不多，体会了，加上按键切换波形就好了

作者: wxc941112 时间: 2016-12-29 21:39
看不出来呢，，，，，

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