标题: proteus双色点阵显示仿真及源程序 [打印本页]
作者: a418230350    时间: 2016-12-1 21:37
标题: proteus双色点阵显示仿真及源程序
proteus 双色点阵显示


  1. #include<reg52.h>
  2. #define uint unsigned int
  3. #define uchar unsigned char
  4. sbit ds2  =P3^5;
  5. sbit ds1  =P3^4;
  6. sbit e    =P3^3;
  7. sbit st_cp=P2^7;
  8. sbit sh_cp=P2^6;
  9. sbit k_y  =P3^2;
  10. sbit k_dw =P3^7;
  11. sbit k_up =P3^6;
  12. uint g,h,i,j,k,l,m;
  13. uint code display[]={

  15. 0x00,0x00,0x00,0x10,0x80,0x08,0x20,0x05,0x20,0x07,0xD0,0x0D,0x30,0x00,0x00,0x08,
  16. 0x80,0x08,0x20,0x05,0x10,0x07,0xF0,0x0C,0x10,0x18,0x00,0x10,0x00,0x10,0x00,0x00,/*"双",0*/
  17. /* (16 X 16 , 楷体 ) */
  18. 0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x1F,0x90,0x24,0x88,0x24,0xCE,0x43,0x6A,0x42,
  19. 0x58,0x42,0xC8,0x41,0x40,0x20,0x00,0x20,0x00,0x20,0x00,0x38,0x00,0x00,0x00,0x00,/*"色",1*/
  20. /* (16 X 16 , 楷体 ) */
  21. 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
  22. 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,

  24. 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
  25. 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,

  27. 0x00,0x00,0x00,0x00,0x00,0x70,0x00,0x00,0x80,0x00,0x80,0x07,0x80,0x34,0xFC,0x04,
  28. 0x94,0x04,0x90,0x34,0x90,0x03,0x88,0x00,0x00,0x18,0x00,0x30,0x00,0x20,0x00,0x00,/*"点",2*/
  29. /* (16 X 16 , 楷体 ) */
  30. 0x00,0x00,0x00,0x00,0xF8,0x3F,0x08,0x00,0xF8,0x00,0x8C,0x00,0x10,0x05,0xD0,0x05,
  31. 0x30,0x05,0xDC,0x7F,0x90,0x04,0x88,0x04,0x88,0x04,0x00,0x04,0x00,0x00,0x00,0x00,/*"阵",3*/

  33. /* (16 X 16 , 楷体 ) */
  34. 0x00,0x00,0x80,0x00,0xC0,0x12,0xA0,0x13,0x98,0x0A,0x60,0x0A,0x00,0x02,0x20,0x01,
  35. 0x50,0x11,0xCC,0x34,0xF0,0x64,0x90,0x01,0x00,0x01,0x00,0x01,0x00,0x00,0x00,0x00,/*"终",4*/
  36. /* (16 X 16 , 楷体 ) */
  37. 0x00,0x00,0x00,0x00,0x80,0x00,0x80,0x00,0x88,0x00,0x88,0x20,0x88,0x40,0xB8,0x60,
  38. 0xD8,0x3F,0x48,0x00,0x44,0x00,0x40,0x00,0x40,0x00,0x40,0x00,0x40,0x00,0x00,0x00,/*"于",5*/
  39. /* (16 X 16 , 楷体 ) */
  40. 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
  41. 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,

  43. 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
  44. 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,

  46. 0x00,0x00,0x00,0x20,0x00,0x10,0xC0,0x0F,0x40,0x02,0x40,0x12,0x42,0x3D,0x3E,0x02,
  47. 0xE0,0x10,0x20,0x0B,0x04,0x0C,0x80,0x13,0x00,0x20,0x00,0x40,0x00,0x70,0x00,0x00,/*"成",6*/
  48. /* (16 X 16 , 楷体 ) */
  49. 0x00,0x00,0x00,0x04,0x20,0x04,0x20,0x04,0xE0,0x03,0x20,0x22,0x10,0x12,0x40,0x09,
  50. 0x40,0x04,0xC0,0x03,0x7C,0x30,0x40,0x30,0x20,0x1E,0xE0,0x01,0x00,0x00,0x00,0x00,/*"功",7*/
  51. /* (16 X 16 , 楷体 ) */

  53. };

  55. void delay(uint d)
  56. {
  57.   while(d--);
  58. }

  60. void  hc_595(uchar dat1,uchar dat2)
  61. {
  62.    uchar i;
  63.    for(i=0;i<8;i++)
  64.      {
  65.        ds1=dat1&0x80;
  66.        ds2=dat2&0x80;
  67.        sh_cp=0;
  68.        sh_cp=1;
  69.        dat1<<=1;
  70.        dat2<<=1;
  71.      }       
  72. }

  74. void ps() interrupt 1
  75. {

  77. }

  79. main()
  80. {
  81. IE=0x8a;TMOD=0x11;
  82. m=sizeof(display)/2-128;
  83. while(1)
  84.   {
  85.    j=0;h=0;
  86.    for(l=0;l<142;l++)
  87.    {
  88.    for(k=0;k<10;k++)
  89.    for(i=0;i<32;i+=2)
  90.     {
  91.      g=i/2%2&&l%2;
  92.      hc_595(display[97+i+j+h]+0x80-0x80*g,0x80*g);
  93.      hc_595(display[96+i+j+h]+0x01-g,g);

  95.      hc_595(display[65+i+j+h]+0x80-0x80*g,0x80*g);
  96.      hc_595(display[64+i+j+h]+0x01-g,g);

  98.      hc_595(0x80-0x80*g,display[97+i-j+h]+0x80*g);
  99.      hc_595(0x01-g,display[96+i-j+h]+g);

  101.      hc_595(0x80-0x80*g,display[65+i-j+h]+0x80*g);
  102.      hc_595(0x01-g,display[64+i-j+h]+g);
  103.      st_cp=0;e=1;
  104.      st_cp=1;
  105.      P1=i/2;
  106.      e=0;
  107.     }
  108.    if      (l<32)         j+=2;
  109.    else if (l>37&&l<70)   j-=2;                 //0+31+5=36
  110.    else if (l==70)        h=192;
  111.    else if (l>70&&l<103)  j+=2;
  112.    else if (l>108)        j-=2;                 //71+31+5=107
  113.    }


  116.    
  117.   }
  118. }
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