tlc2543AD转换的实现

ID:278851 · 发表于 2018-1-25 15:53

代码如下

#include <reg52.h>
#include <intrins.h>
sbit CLOCK=P1^6; /*2543时钟*/
sbit D_IN=P1^4 ;/*2543输入*/
sbit D_OUT=P1^3; /*2543输出*/
sbit _CS=P1^5; /*2543片选*/
#define uint unsigned int
#define uchar unsigned char
uchar code string[16]={"value of v"};
uchar code DispStr[16]={"TLM2543"};
sbit lcden=P3^4;
sbit lcdrs=P3^5;
sbit dula=P2^6;
sbit wela=P2^7;
void display(); //待显温度值转换
void delay(uchar n)
{
uchar i;
for(i=0;i<n;i++)
{
_nop_();
}
}
uint read2543(uchar port)
{
uint ad=0,i;
CLOCK=0;
_CS=0;
port<<=4;
for(i=0;i<12;i++)
{
if(D_OUT) ad|=0x01;
D_IN=(bit)(port&0x80);
CLOCK=1;
delay(3);
CLOCK=0;
delay(3);
port<<=1;
ad<<=1;
}
_CS=1;
ad>>=1;
return(ad);
}
void DelayMs(uint z)
{
uint x,y;
for(x=z;x>0;x--)
for(y=110;y>0;y--);
}
void write_com(uchar com)//write common
{
lcdrs=0;
P0=com;
DelayMs(5);
lcden=1;
DelayMs(5);
lcden=0;
}
void write_data(uchar date) //write data
{
lcdrs=1;
P0=date;
DelayMs(5);
lcden=1;
DelayMs(5);
lcden=0;
}
void LCDInit()
{
dula=0;
wela=0;
lcden=0;
write_com(0x38);//dispaly mode
write_com(0x0c);// guanbiaoshanshuo
write_com(0x06);
write_com(0x01);//clear displayer
write_com(0x80);//*p
}
DisplayChar(uchar X, uchar Y, uchar DData)
{
Y &= 0x1;
X &= 0xF; //限制X不能大于15，Y不能大于1
if (Y) X |= 0x40; //当要显示第二行时地址码+0x40;
X |= 0x80; // 算出指令码
write_com(X); //这里不检测忙信号，发送地址码
write_data(DData);
return X;
}
DisplayStr(uchar X,uchar Y,uchar code *DData)
{
uchar ListLength;
ListLength = 0;
Y &= 0x1;
X &= 0xF; //限制X不能大于15，Y不能大于1
while (DData[ListLength]>0x20) //若到达字
{
if (X <= 0xF) //X坐标应小于0xF
{
DisplayChar(X, Y, DData[ListLength]); //显示单个字符
ListLength++;
X++;
}
}
return X ;
}
void main()
{
uint ad,ad1,ad_val,ad_val1;
DelayMs(255);//等待电源稳定,液晶复位完成
LCDInit(); //1602 液晶初始化
DisplayStr(0,0,string);//显示"温度:"
DisplayStr(0,1,DispStr);//显示"系列号"
DelayMs(250);
DelayMs(250);
DelayMs(250);
DelayMs(250);
DelayMs(250);
write_com(0x01); // 清屏
DelayMs(50);
ad=read2543(0);
DelayMs(50);
ad1=read2543(1);
ad_val = (uint)(((ad*5.0)/4096.0)*10000);
ad_val1 = (uint)(((ad1*5.0)/4096.0)*10000);
while(1)
{
display();
}
}
void display()
{
uint ad_val,ad_val1;
uint ge,x1,x2,x3,x4,ge1,x11,x21,x31,x41;
ge = ad_val/10000;
x1 = ad_val%10000/1000;
x2 = ad_val%1000/100;
x3 = ad_val%100/10;
x4 = ad_val%10;
ge1 = ad_val1/10000;
x11 = ad_val1%10000/1000;
x21 = ad_val1%1000/100;
x31 = ad_val1%100/10;
x41 = ad_val1%10;
DisplayChar(4,0,ge+0x30);//个位
DisplayChar(5,0,0x2e); //小数点 .
DisplayChar(6,0,x1+0x30);
DisplayChar(7,0,x2+0x30);
DisplayChar(8,0,x3+0x30);
DisplayChar(9,0,x4+0x30);
DisplayChar(10,0,'V');
DisplayChar(4,1,ge1+0x30);//个位
DisplayChar(5,1,0x2e); //小数点 .
DisplayChar(6,1,x11+0x30);
DisplayChar(7,1,x21+0x30);
DisplayChar(8,1,x31+0x30);
DisplayChar(9,1,x41+0x30);
DisplayChar(10,1,'V');
ad_val = (uint)(((read2543(0)*5.0)/4096.0)*10000);//不断扫描
ad_val1 = (uint)(((read2543(1)*5.0)/4096.0)*10000);//不断扫描
}

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