单片机控制直流电机的驱动及正反转程序+Proteus仿真

ID:536805 · 发表于 2019-5-22 01:04

关于直流电机的驱动电路仿真原理图如下（proteus仿真工程文件可到本帖附件中下载）

单片机源程序如下:

//四个按键控制步进电机：正转，反转，加1，减1
//上电时电机启动，加减档位，电机采用单双八拍方式
#include<reg51.h>
#define uchar unsigned char
#define uint unsigned int
sbit s1 = P1^0;
sbit s2 = P1^1;
sbit s3 = P3^0;
sbit s4 = P3^1;
sbit s5 = P3^2;//按键定义,s1正转，s2反转，s3加1，s4减1
sbit a = P2^7;sbit b = P2^6;sbit c = P2^5;sbit d = P2^4;//脉冲信号输入端定义
uchar code time_counter[10][2]={{0xda,0x1c},{0xde,0xe4},{0xe1,0xec},{0xe5,0xd4},{0xe9,0xbc}, //9.7 ----1ms
{0xed,0xa4},{0xf1,0x8c},{0xf5,0x74},{0xf9,0x5c},{0xfc,0x18}};
uchar num1 = 0;//控制取励磁信号变量
uchar num2 = 8;
char k=0;//加减档位控制，1为最小档
char pause=1;//暂停时保存之前的转速，开机默认1
bit flag1 = 0;//初始正转，正反转标志
//================================定时器0/1初始化函数================================
void T0_T1_init()
{
TMOD = 0x11;//定时器0/1均工作于方式1,16位计时方式
TH1 = time_counter[k-1][0];
TL1 = time_counter[k-1][1];//定时器1，定时10ms用于步进电机转速控制
TR1 = 0;
ET1= 1;//开定时器中断
EA = 1;//开总中断
}
//================================ms级延时函数=======================================
void delay1m(uint x)
{
uint i,j;
for(i=0;i<x;i++) //连数x次，约 x ms
for(j=0;j<120;j++); //数120 次，约1 ms
}
//================================主函数=============================================
void main()
{
T0_T1_init();
a=b=c=d=0;
while(1)
{
if(s1 == 0)
{
delay1m(3);
if(s1 == 0)
{
flag1 = 0;//正转
}
while(!s1);
}
if(s2 == 0 )
{
delay1m(3);
if(s2 == 0)
{
flag1 = 1;//反转
}
while(!s2);
}
if(s3 == 0) //速度加1档
{
delay1m(3);
if(s3 == 0)
{
k++;
TR1=1;
if(k > 10 )
{
k = 1;
}
}
while(!s3);
}
if(s4 == 0) //速度减1档
{
delay1m(3);
if(s4 == 0)
{
k--;
TR1=1;
if(k <= 0)
{
k = 10;
}
}
while(!s4);
}
if(s5==0)
{
delay1m(3);
if(s5==0)
{
if(TR1==1)
{
pause=k;
k=0;
TR1=0;
a=b=c=d=0;
}
else if(TR1==0)
{
k=pause;
TR1=1;
}
while(!s5);
}
}
}
}
//==================================定时器1中断函数，用于脉冲频率控制=====================================
void time1_interrupt()interrupt 3
{
static num1 = 0;
static num2 = 0;
TH1 = time_counter[k-1][0];
TL1 = time_counter[k-1][1];//定时器1，定时1 用于步进电机转速控制
if(flag1 == 0)//正转
{
switch(num1)
{
case 0:a = 1;b = 0;c = 0;d = 0;break;
case 1:a = 1;b = 1;c = 0;d = 0;break;
case 2:a = 0;b = 1;c = 0;d = 0;break;
case 3:a = 0;b = 1;c = 1;d = 0;break;
case 4:a = 0;b = 0;c = 1;d = 0;break;
case 5:a = 0;b = 0;c = 1;d = 1;break;
case 6:a = 0;b = 0;c = 0;d = 1;break;
case 7:a = 1;b = 0;c = 0;d = 1;break;
}
num1++;
if(num1 == 8)num1 = 0;
}
else //反转
{
switch(num2)
{
case 0:a = 1;b = 0;c = 0;d = 1;break;
case 1:a = 0;b = 0;c = 0;d = 1;break;
case 2:a = 0;b = 0;c = 1;d = 1;break;
case 3:a = 0;b = 0;c = 1;d = 0;break;
case 4:a = 0;b = 1;c = 1;d = 0;break;
case 5:a = 0;b = 1;c = 0;d = 0;break;
case 6:a = 1;b = 1;c = 0;d = 0;break;
case 7:a = 1;b = 0;c = 0;d = 0;break;
}
num2++;
if(num2 == 8)num2 = 0;
}
}

复制代码

所有资料51hei提供下载:

新建文件夹.7z (16.2 KB, 下载次数: 146)

ID:630909 · 发表于 2019-10-27 15:08

   TH1 = time_counter[k-1][0];
      TL1 = time_counter[k-1][1];//定时器1，定时10ms用于步进电机转速控制
我能问问这个k-1是什么意思还有10ms是如何定时的

uchar code time_counter[10][2]={{0xda,0x1c},{0xde,0xe4},{0xe1,0xec},{0xe5,0xd4},{0xe9,0xbc},  //9.7 ----1ms
                                                         {0xed,0xa4},{0xf1,0x8c},{0xf5,0x74},    这段我也不太懂可以解答下吗谢谢

ID:673985 · 发表于 2019-12-27 22:18

不错的资料！！

ID:792366 · 发表于 2020-6-29 09:39

kellyqian 发表于 2019-10-27 15:08
TH1 = time_counter[k-1][0];
TL1 = time_counter[k-1][1];//定时器1，定时10ms用于步进电 ...

我觉得太棒了

ID:852834 · 发表于 2020-12-15 20:01

不行啊

ID:852834 · 发表于 2020-12-15 20:35

qweasdl 发表于 2020-6-29 09:39
我觉得太棒了

可以运行成功吗，为啥我的不行

ID:908382 · 发表于 2021-4-20 16:38

相当不错的参考资料感谢分享唯一区别是和我用的型号不太一样

帐号		自动登录	找回密码
密码			立即注册