单片机+LED点阵显示字幕不全怎么解决?

ID:774521 · 发表于 2020-6-12 00:44

本帖最后由大智慧152 于 2020-6-12 13:06 编辑

如图两个字模是相同的,主要参考https://blog.csdn.net/zh_j_wei/article/details/104192813所写但是最终显示字模不完全
附上源代码

#include <reg51.h>
#include <intrins.h>
#define GPIO_KEY P1 //独立键盘用P1口
//--重定义函数变量--//
#define uchar unsigned char
#define uint unsigned int
#define ulong unsigned long
unsigned char Key_Scan();
void Delay10ms(uint z);
void translation();
void twinkle1();
void twinkle2();
uint k,i,j,ms;
uchar keyNum;
//--定义SPI要使用的 IO--//
sbit MOSIO = P3^4;
sbit R_CLK = P3^5;
sbit S_CLK = P3^6;
//通过74HC595发送四个字节的数据
void HC595SendData(uchar BT3, uchar BT2,uchar BT1,uchar BT0)
{
uchar i;
//--发送第一个字节--//
for(i=0;i<8;i++)
{
MOSIO = BT3 >> 7; //从高位到低位
BT3 <<= 1; //左移一位
S_CLK = 0;
S_CLK = 1;
}
//--发送第二个字节--//
for(i=0;i<8;i++)
{
MOSIO = BT2 >> 7; //从高位到低位
BT2 <<= 1;
S_CLK = 0;
S_CLK = 1;
}
//--发送第三个字节--//
for(i=0;i<8;i++)
{
MOSIO = BT1 >> 7; //从高位到低位
BT1 <<= 1;
S_CLK = 0;
S_CLK = 1;
}
//--发送第四个字节--//
for(i=0;i<8;i++)
{
MOSIO = BT0 >> 7; //从高位到低位
BT0 <<= 1;
S_CLK = 0;
S_CLK = 1;
}
//--输出--//
R_CLK = 0; //set dataline low
R_CLK = 1; //片选
R_CLK = 0; //set dataline low
}
//点阵显示数组
uchar code tab0[] = {0x00, 0x01, 0x00, 0x02, 0x00, 0x04, 0x00, 0x08,
0x00, 0x10, 0x00, 0x20, 0x00, 0x40, 0x00, 0x80,
0x01, 0x00, 0x02, 0x00, 0x04, 0x00, 0x08, 0x00,
0x10, 0x00, 0x20, 0x00, 0x40, 0x00, 0x80, 0x00};
//--张--//
uchar code tab1[] = {128,1,191,49,176,49,176,25,176,13,190,7,134,1,230,255,134,7,190,13,176,13,176,25,176,49,176,103,158,195,140,1};
//--李--//
uchar code tab2[] = {128,0,128,0,254,63,160,2,144,4,136,8,6,48,240,3,0,1,128,0,254,63,128,0,128,0,224,0,0,0,0,0};
//--王--//
uchar code tab3[] = {0,0,252,31,128,0,128,0,128,0,128,0,128,0,248,15,128,0,128,0,128,0,128,0,128,0,254,63,0,0,0,0};
//--任--//
uchar code tab4[] = {16,0,16,28,208,3,8,2,8,2,12,2,10,2,232,63,8,2,8,2,8,2,8,2,8,2,200,31,0,0,0,0};
//--徐-//
uchar code tab5[] = {16,2,16,2,8,5,132,8,82,16,176,47,8,2,12,2,202,31,8,2,72,18,72,34,40,34,136,3,0,0,0,0};
//--五角星--//
uchar code char1[] = {128,1,128,1,192,3,192,3,192,3,96,6,127,254,6,96,28,56,48,12,48,12,152,27,248,30,56,28,12,48,0,0};
//--圆--//
uchar code char2[] = {0,0,224,7,120,30,28,56,28,56,14,112,14,112,14,112,14,112,14,112,28,56,28,56,120,30,224,7,0,0,0,0};
//--三角--//
uchar code char3[] = {0,0,128,1,128,1,192,3,192,3,96,6,96,6,48,12,48,12,24,24,24,24,12,48,12,48,254,127,0,0,0,0};
//--菱形--//
uchar code char4[] = {128,0,64,1,32,2,16,4,8,8,4,16,2,32,1,64,2,32,4,16,8,8,16,4,32,2,64,1,128,0,0,0};
//--箭头--//
uchar code char5[] = {0,0,0,0,0,0,0,2,0,4,0,8,0,16,0,32,126,64,0,32,0,16,0,8,0,4,0,2,0,0,0,0};
uchar *p[] = {tab1, tab2, tab3, tab4, tab5};
uchar *c[] = {char1, char2, char3, char4,char5};
void main(void)
{
while(1)//死循环
{
HC595SendData(0xff,0xff,0,0); //清屏
keyNum=Key_Scan(); //读取键值
switch (keyNum)
{
case(0xFE) : //返回按键K1的数据
translation();//文字从上到下平移
break;
case(0xFD) : //返回按键K2的数据
twinkle1(); //文字闪烁
break;
case(0xFB) : //返回按键K3的数据
twinkle2(); //符号闪烁
break;
case(0x7F) : //返回按键K0的数据
HC595SendData(0xff,0xff,0,0); //清屏
break;
default:
break;
}
}
}
unsigned char Key_Scan()
{
unsigned char keyValue = 0 , i; //保存键值
//--检测按键1--//
if (GPIO_KEY != 0xFF) //检测按键K1是否按下
{
Delay10ms(5); //消除抖动
if (GPIO_KEY != 0xFF) //再次检测按键是否按下
{
keyValue = GPIO_KEY;
i = 0;
while ((i<50) && (GPIO_KEY != 0xFF)) //检测按键是否松开
{
Delay10ms(5);
i++;
}
}
}
return keyValue; //将读取到键值的值返回
}
//消除抖动(延时)
void Delay10ms(uint z)
{
uint j;
while(z--)
{
j=5000;
while(j--);
}
}
//文字由上而下平移
void translation()
{
j=0;
while(keyNum!=0x7F)
{
for(ms = 10; ms > 0; ms--) //移动定格时间设置
{
for(k = 0; k < 16; k++) //显示一个字
{
HC595SendData(~(*(p[0] + 2*(k+j) + 1)),~(*(p[0] + 2*(k+j) )),
tab0[2*k],tab0[2*k + 1]);
//因为字模软件取的数组是高电平有效，所以列要取反
keyNum=Key_Scan();
if(keyNum==0x7F)
break;
}
HC595SendData(0xff,0xff,0,0); //清屏
if(keyNum==0x7F)
break;
}
j++;
if(j == (10*15) )
{
j = 0;
}
}
}
//文字闪烁
void twinkle1()
{
while(keyNum!=0x7F)
{
for(i = 0; i < 5; i++) //总共5个字
{
for(ms = 50; ms > 0; ms--) //显示50次，即肉眼可识别的停留时间
{
for(k = 0; k < 16; k++) //显示一个字
{
//--因为字模软件取的数组是高电平有效，所以列要取反--//
HC595SendData(~(*(p[i] + 2*k + 1)),~(*(p[i] + 2*k )),
tab0[2*k],tab0[2*k + 1]);
keyNum=Key_Scan();
if(keyNum==0x7F)
break;
}
HC595SendData(0xff,0xff,0,0); //清屏
if(keyNum==0x7F)
break;
}
if(keyNum==0x7F)
break;
}
}
}
//符号闪烁
void twinkle2()
{
while(keyNum!=0x7F)
{
for(i = 0; i <5; i++) //总共5个符号
{
for(ms = 50; ms > 0; ms--) //显示50次，即肉眼可识别的停留时间
{
for(k = 0; k < 16; k++) //显示一个字
{
//--因为字模软件取的数组是高电平有效，所以列要取反--//
HC595SendData(~(*(c[i] + 2*k + 1)),~(*(c[i] + 2*k )),
tab0[2*k],tab0[2*k + 1]);
keyNum=Key_Scan();
if(keyNum==0x7F)
break;
}
HC595SendData(0xff,0xff,0,0); //清屏
if(keyNum==0x7F)
break;
}
if(keyNum==0x7F)
break;
}
}
}

复制代码

proteus和https://blog.csdn.net/zh_j_wei/article/details/104192813上的图是一致的

ID:739545 · 发表于 2020-6-12 10:59

整体是对的，应该是某个连线有问题或者缺失

ID:774521 · 发表于 2020-6-12 13:06

lovezjf234 发表于 2020-6-12 10:59
整体是对的，应该是某个连线有问题或者缺失

我把连线也发出来了可以帮我看看哪里连错了吗

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