单片机按键数码管加减法运算

ID:1107872 · 发表于 2024-1-3 22:04

基于普中单核A4开发板，按键数码管加减法计算：三位数码管显示0~999；独立按键K2按一下，数码管加或者减1；矩阵键盘按一下，数码管加或者减对应的键值，k1键用于清零，k3键用于实现加减法切换，数码管大于999时变为0

单片机源程序如下:

#include <reg52.h>
typedef unsigned char uchar;
typedef unsigned int uint;
uchar GetMatrixKey();
sbit LSA = P2^2;
sbit LSB = P2^3;
sbit LSC = P2^4;
sbit K1 = P3^0; // 清零键
sbit K2 = P3^1; // 加减1键
sbit K3 = P3^2; // 加减法切换键
uchar matrixKey = 0;
uchar code smgduan[10] = {0x3f, 0x06, 0x5b, 0x4f, 0x66, 0x6d, 0x7d, 0x07, 0x7f, 0x6f};
uchar disp_buff[3] = {0, 0, 0};
int num = 0;
bit isAddition = 1; // 默认使用加法
void delay(uint i) {
while (i--);
}
void DigDisplay() {
uchar i;
for (i = 0; i < 3; i++) {
switch (i) {
case 0: LSA = 1; LSB = 0; LSC = 0; break; // 个位
case 1: LSA = 0; LSB = 1; LSC = 0; break; // 十位
case 2: LSA = 0; LSB = 0; LSC = 1; break; // 百位
}
P0 = smgduan[disp_buff[i]];
delay(100);
P0 = 0x00;
}
}
void KeyScan() {
if (K1 == 0) { // 清零键
num = 0;
disp_buff[0] = disp_buff[1] = disp_buff[2] = 0;
while (K1 == 0);
}
if (K2 == 0) { // 加减1键
if (isAddition) {
num = (num + 1) % 1000;
} else {
num = (num == 0) ? 999 : num - 1;
}
disp_buff[0] = num % 10; // 个位
disp_buff[1] = (num / 10) % 10; // 十位
disp_buff[2] = num / 100; // 百位
while (K2 == 0);
}
if (K3 == 0) { // 加减法切换键
isAddition = ~isAddition;
while (K3 == 0);
}
matrixKey = GetMatrixKey();
// 处理矩阵键盘输入
if (matrixKey >= 1 && matrixKey <= 16) {
// 根据矩阵键值加减对应的键值
if (isAddition) {
num = (num + matrixKey) % 1000;
} else {
num = (num - matrixKey + 1000) % 1000;
}
disp_buff[0] = num % 10; // 个位
disp_buff[1] = (num / 10) % 10; // 十位
disp_buff[2] = num / 100; // 百位
}
}
// 获取矩阵键盘的键值，具体根据硬件情况实现
uchar GetMatrixKey() {
uchar KeyNumber = 0;
P1 = 0xFF;
P1_3 = 0;
if (P1_7 == 0) { delay(20); while (P1_7 == 0); delay(20); KeyNumber = 1; }
if (P1_6 == 0) { delay(20); while (P1_6 == 0); delay(20); KeyNumber = 5; }
if (P1_5 == 0) { delay(20); while (P1_5 == 0); delay(20); KeyNumber = 9; }
if (P1_4 == 0) { delay(20); while (P1_4 == 0); delay(20); KeyNumber = 13; }
P1 = 0xFF;
P1_2 = 0;
if (P1_7 == 0) { delay(20); while (P1_7 == 0); delay(20); KeyNumber = 2; }
if (P1_6 == 0) { delay(20); while (P1_6 == 0); delay(20); KeyNumber = 6; }
if (P1_5 == 0) { delay(20); while (P1_5 == 0); delay(20); KeyNumber = 10; }
if (P1_4 == 0) { delay(20); while (P1_4 == 0); delay(20); KeyNumber = 14; }
P1 = 0xFF;
P1_1 = 0;
if (P1_7 == 0) { delay(20); while (P1_7 == 0); delay(20); KeyNumber = 3; }
if (P1_6 == 0) { delay(20); while (P1_6 == 0); delay(20); KeyNumber = 7; }
if (P1_5 == 0) { delay(20); while (P1_5 == 0); delay(20); KeyNumber = 11; }
if (P1_4 == 0) { delay(20); while (P1_4 == 0); delay(20); KeyNumber = 15; }
P1 = 0xFF;
P1_0 = 0;
if (P1_7 == 0) { delay(20); while (P1_7 == 0); delay(20); KeyNumber = 4; }
if (P1_6 == 0) { delay(20); while (P1_6 == 0); delay(20); KeyNumber = 8; }
if (P1_5 == 0) { delay(20); while (P1_5 == 0); delay(20); KeyNumber = 12; }
if (P1_4 == 0) { delay(20); while (P1_4 == 0); delay(20); KeyNumber = 16; }
return KeyNumber;
}
void main() {
while (1) {
KeyScan();
DigDisplay();
}
}