单片机控制16x16点阵显示姓名的仿真原理图与程序

ID:267615 · 发表于 2018-9-24 19:14

自己实训做的，不知道有没有不足的地方，希望指导一下
仿真原理图如下（proteus仿真工程文件可到本帖附件中下载）

单片机源程序如下:

#include "reg51.h"
#define uchar unsigned char
#define uint unsigned int
#define Lie P1
sbit SHCP = P2^0;
sbit DS = P2^1;
sbit STCP = P2^2;
uchar code led[ ] ={
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0xFE,0xFF,0x22,0x04,0x5A,0x08,0x86,0x07,0x08,0x20,0x88,0x11,0x68,0x0D,
0x18,0x41,0x0F,0x81,0xE8,0x7F,0x08,0x01,0x08,0x05,0x08,0x09,0x08,0x30,0x00,0x00, // 陈
0x00,0x40,0x00,0x38,0xFC,0x00,0x44,0x00,0x44,0x3C,0x44,0x40,0x44,0x40,0xFF,0x43,
0x44,0x4C,0x44,0x40,0x44,0x40,0x44,0x70,0xFC,0x04,0x00,0x08,0x00,0x30,0x00,0x00, //忠
0x20,0x04,0x10,0x04,0x08,0x04,0xFC,0x05,0x03,0x04,0x20,0x04,0x20,0x04,0x10,0xFF,
0x7F,0x04,0x88,0x04,0x88,0x04,0x84,0x04,0x82,0x04,0xE0,0x04,0x00,0x04,0x00,0x00, //华
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00
};
//uchar led[]={}
void shift16bit(uchar dat1,uchar dat2) //595输出16位数据
{
uchar i;
STCP=0;
for(i=0;i<8;i++)
{
SHCP=0;
if(dat1 &0x80) DS=1;
else DS=0;
dat1<<=1;
SHCP=1;
}
for(i=0;i<8;i++)
{
SHCP=0;
if(dat2 &0x80) DS=1;
else DS=0;
dat2<<=1;
SHCP=1;
}
STCP=1;
}
void delay(uint x)
{
uint i;
for(i=0;i<x;i++);
}
void main()
{
uchar i,x=0;
uint n;
while(1)
{
for(n=0;n<10;n++)
for(i=0;i<16;i++)
{
Lie=i;
shift16bit(led[2*i+1+2*x],led[2*i+2*x]);
delay(10);
}
x++;
if(x==48) x=0;
/*
for(n=0;n<100;n++)
for(i=0;i<16;i++)
{
Lie= i;
shift16bit(led[x][2*i+1],led[x][2*i]);
delay(100);
}
x++;
if(x==4) x=0;
*/
}
}