单片机源程序如下:
- #include "bjdj.h"
- #include "delay.h"
- #define uint unsigned int
-
- //步进电机正反转数组1
- uint16_t phasecw[4] ={0x0200,0x0100,0x0080,0x0040};// D-C-B-A
- uint16_t phaseccw[4]={0x0040,0x0080,0x0100,0x0200};// A-B-C-D.
- //步进电机正反转数组2
- uint16_t phasecw1[4] ={0x0800,0x0400,0x0200,0x0100};// D-C-B-A
- uint16_t phaseccw1[4]={0x0100,0x0200,0x0400,0x0800};// A-B-C-D.
- void Delay_xms(uint x)
- {
- uint i,j;
- for(i=0;i<x;i++)
- for(j=0;j<112;j++);
- }
- void Moto_Init(void)
- {
- //电机1
- // IN4: PC9 d
- // IN3: PC8 c
- // IN2: PC7 b
- // IN1: PC6 a
- RCC->APB2ENR|=1<<4; //使能PORTC时钟
- GPIOC->CRL&=0X00FFFFFF;
- GPIOC->CRL|=0X33000000; //PC6,PC7 推挽输出
- GPIOC->ODR=3<<6; //PC6,PC7上拉输出高
-
- GPIOC->CRH&=0XFFFFFF00;
- GPIOC->CRH|=0X00000033; //PC8,PC9 推挽输出
- GPIOC->ODR=3<<8; ////PC8,PC9上拉输出高
-
- //电机2
- // IN4: PD11 d
- // IN3: PD10 c
- // IN2: PD9 b
- // IN1: PD8 a
- RCC->APB2ENR|=1<<5; //使能PORTD时钟
- GPIOD->CRH&=0XFFFF0000;
- GPIOD->CRH|=0X00003333; //PC8,PC9,PC10,PC11 推挽输出
- GPIOD->ODR=15<<8; ////PC8,PC9,PC10,PC11上拉输出高
- }
- void Motorcw(uint speed) //电机1逆时针
- {
- uint8_t i=0;
-
- for(i=0;i<4;i++)
- {
- GPIOC->ODR = phasecw[i];
- delay_ms(speed);
- }
- }
- void Motorcw1(int speed) //电机2逆时针
- {
- uint8_t i;
-
- for(i=0;i<4;i++)
- {
- GPIOD->ODR = phasecw1[i];
- delay_ms(speed);
- }
- }
- void Motorccw(int speed) //电机1顺时针
- {
- uint8_t i;
- for(i=0;i<4;i++)
- {
- GPIOC->ODR = phaseccw[i];
- delay_ms(speed);
- }
- }
- void Motorccw1(int speed) //电机2顺时针
- {
- uint8_t i;
-
- for(i=0;i<4;i++)
- {
- GPIOD->ODR = phaseccw1[i];
- delay_ms(speed);
- }
- }
- void MotorStop(void)
- {
- GPIOC->ODR = 0x0000;
- }
- void MotorStop1(void)
- {
- GPIOD->ODR = 0x0000;
- }
- //由于 *一个脉冲* *输出轴* 转0.08789度(电机实转0.08789*64=5.625度),即步进角为5.625度。
- //则转完A-B-C-D为 *8个脉冲* ,即0.08789*8=0.70312度。若称A-B-C-D为一个周期,则j为需要的转完angle角度所需的周期数。
- void Motorcw_angle(int angle,int speed) //电机1逆时针
- {
- int i,j;
- j=(int)(angle/0.70312);
- for(i=0;i<j;i++)
- {
- Motorcw(speed);
- }
- }
- void Motorcw_angle1(int angle,int speed) //电机2逆时针
- {
- int i,j;
- j=(int)(angle/0.70312);
- for(i=0;i<j;i++)
- {
- Motorcw1(speed);
- }
- }
- void Motorccw_angle(int angle,int speed) //电机1顺时针
- {
- int i,j;
- j=(int)(angle/0.70312);
- for(i=0;i<j;i++)
- {
- Motorccw(speed);
- }
- }
- void Motorccw_angle1(int angle,int speed) //电机2顺时针
- {
- int i,j;
- j=(int)(angle/0.70312);
- for(i=0;i<j;i++)
- {
- Motorccw1(speed);
- }
- }
复制代码
所有资料51hei提供下载:
ULN2003驱动28BYJ-48步进电机.rar
(282.93 KB, 下载次数: 138)
|