基于dac0832的单极性输出电路，可输出三种波

ID:625113 · 发表于 2019-11-23 08:31

#include <reg51.h>
#define DAC P0
sbit CS1=P2^0;
sbit WRR=P3^6;

static unsigned char code TableSin[256]={
128,131,134,137,140,143,146,149,152,155,158,162,165,167,170,173,
176,179,182,185,188,190,193,196,198,201,203,206,208,211,213,215,
218,220,222,224,226,228,230,232,234,235,237,238,240,241,243,244,
245,246,248,249,250,250,251,252,253,253,254,254,254,255,255,255,
255,255,255,255,254,254,254,253,253,252,251,250,250,249,248,246,
245,244,243,241,240,238,237,235,234,232,230,228,226,224,222,220,
218,215,213,211,208,206,203,201,198,196,193,190,188,185,182,179,
176,173,170,167,165,162,158,155,152,149,146,143,140,137,134,131,
127,124,121,118,115,112,109,106,103,100, 97, 93, 90, 88, 85, 82,
79, 76, 73, 70, 67, 65, 62, 59, 57, 54, 52, 49, 47, 44, 42, 40,
37, 35, 33, 31, 29, 27, 25, 23, 21, 20, 18, 17, 15, 14, 12, 11,
10,  9,  7,  6,  5,  5,  4,  3,  2,  2,  1,  1,  1,  0,  0,  0,
  0,  0,  0,  0,  1,  1,  1,  2,  2,  3,  4,  5,  5,  6,  7,  9,
10, 11, 12, 14, 15, 17, 18, 20, 21, 23, 25, 27, 29, 31, 33, 35,
37, 40, 42, 44, 47, 49, 52, 54, 57, 59, 62, 65, 67, 70, 73, 76,
79, 82, 85, 88, 90, 93, 97,100,103,106,109,112,115,118,121,124
};

unsigned char i;
unsigned char num=1;
void tran();
void sin();
void puls();
void delay(unsigned char);
void init();
void main()
{
CS1=0;
WRR=0;
init();
while(1)
{
   switch(num)
   {
      case 1:sin();break;
case 2:puls(); break;
case 3:tran();break;
   }
}

}

void wave_t() interrupt 0
{
delay(100);
num++;
if(num>3)num=1;
}
void delay(unsigned char i)
{
while(i--);
}
void sin()
{
for(i=0;i<254;i++)
{
DAC=TableSin[i];
delay(3);
}
}
void tran()
{
unsigned char i;
for(i=0;i<254;i+=2)
{
DAC=i;
delay(2);
}
for(i=254;i>=1;i-=2)
{
DAC=i;
delay(2);
}
}
void puls()
{
DAC=0xff;
delay(1000);
DAC=0x00;
delay(1000);

}
void init()
{
IT0=1;
EX0=1;
EA=1;
}

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