这个程序里面,如果数码管显示程序不在WHILE(1)的内部,58就可以显示在数码管上,如果把它放在WHILE(1)里面,如上面的程序那样,只能读出来
最后一位8,前一位5闪一下就没了。这是为什么?如果必须有WHILE(1)的话,请大师傅帮解决一下。谢谢- include<reg52.h>
- sbit dula=P2^6;
- sbit wela=P2^7;
- #define uchar unsigned char
- #define uint unsigned int
- uchar code table[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79 ,0x71};
- void delay(uchar a)
- {
- uchar x,y;
- for(x=a;x>0;x--)
- for( y=109;y>0;y--);
- }
- void main()
- {
- uchar read=0x58;
- bit read_ok=1;
- while(1)
- {
- if(read_ok)
- {
- read_ok=0;
-
- wela=1;
- P0=0xfe;
- wela=0;
- dula=1;
- P0=table[read/16];
- dula=0;
- delay(5);
- wela=1;
- P0=0xfd;
- wela=0;
- dula=1;
- P0=table[read%16];
- dula=0;
- delay(5);
-
- }
-
-
- }
- }
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