这是《手把手教你学单片机》里的教程，想问一下switch语句中给ADDR1,2,0赋值想表达的是什么意思
单片机源程序如下:
- #include<reg52.h>
- sbit ADDR0 = P1^0;
- sbit ADDR1 = P1^1;
- sbit ADDR2 = P1^2;
- sbit ADDR3 = P1^3;
- sbit ENLED = P1^4;
- unsigned char code LedChar[]={
- 0xC0, 0xF9, 0xA4, 0xB0, 0x99, 0x92, 0x82, 0xF8,
- 0x80, 0x90, 0x88, 0x83, 0xC6, 0xA1, 0x86, 0x8E
- };
- unsigned char LedBuff[6]={
- 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF
- };
- void main()
- {
- unsigned int cnt = 0;
- unsigned long sec = 0;
- unsigned char i = 0;
- ENLED = 0;
- ADDR3 = 1;
- TMOD = 0x01;
- TH0 = 0xFC;
- TL0 = 0x67;
- TR0 = 1;
- while(1)
- {
- if(TF0 ==1)
- {
- TF0 = 0;
- TH0 = 0xFC;
- TL0 = 0x67;
- cnt++;
- if(cnt >= 1000)
- {
- cnt = 0;
- sec++;
- LedBuff[0] = LedChar[sec%10];
- LedBuff[1] = LedChar[sec/10%10];
- LedBuff[2] = LedChar[sec/100%10];
- LedBuff[3] = LedChar[sec/1000%10];
- LedBuff[4] = LedChar[sec/10000%10];
- LedBuff[5] = LedChar[sec/100000%10];
- }
- P0 = 0xFF;
- switch(i)
- {
- case 0: ADDR2=0; ADDR1=0; ADDR0=0; i++; P0=LedBuff[0];break;
- case 1: ADDR2=0; ADDR1=0; ADDR0=1; i++; P0=LedBuff[1];break;
- case 2: ADDR2=0; ADDR1=1; ADDR0=0; i++; P0=LedBuff[2];break;
- case 3: ADDR2=0; ADDR1=1; ADDR0=1; i++; P0=LedBuff[3];break;
- case 4: ADDR2=1; ADDR1=0; ADDR0=0; i++; P0=LedBuff[4];break;
- case 5: ADDR2=1; ADDR1=0; ADDR0=1; i=0; P0=LedBuff[5];break;
- default:break;
- }
- }
- }
- }
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