为什么我上一个lcd1602函数能读取到temp,但是在报警中却读取不了temp

ID:699723 · 发表于 2020-3-13 14:09

相关如下
void LcdDisplay(int temp)得temp能用，但是void warn(int temp)说我的temp没定义？
程序如下
void LcdDisplay(int temp)
{
unsigned char  datas[] = {0, 0, 0, 0, 0};
unsigned char TempH,TempL;
if(temp&0x8000)
{
  LcdWriteCom(0x85);
  LcdWriteData('-');
  temp=~temp;
  temp +=1;
}
else
{
  LcdWriteCom(0x85);
  LcdWriteData('+');
}
TempH=temp>>4;
TempL=temp&0x0F;
TempL=TempL*6.25+0.5;
datas[0] = TempH/100%10;
datas[1] = TempH/10%10;
datas[2] = TempH%10;
datas[3] = TempL/10%10;
datas[4] = TempL%10;

LcdWriteCom(0x86);
LcdWriteData('0'+datas[0]);

LcdWriteCom(0x87);
LcdWriteData('0'+datas[1]);

LcdWriteCom(0x88);
LcdWriteData('0'+datas[2]);

LcdWriteCom(0x89);
LcdWriteData('.');

LcdWriteCom(0x8a);
LcdWriteData('0'+datas[3]);

}
void warn(int temp)
{
if(temp>=27)
{
  beep=~beep;
  delay(50);
}

}