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问题详述：当液晶显示时间时，时间不能顺着table1中的值继续加，比如刚通电秒显示的是50，然后跳一秒立马01开始了，而经过按键尽心设置的时间就可以跟着设置的值，想优化下让他能够根据输入的时间直接进行累加，而不是动一秒返回01重新开始。
附件说明：开发板原理图。
图片说明：程序现象。
以下为全部单片机程序：
#include <REGX52.H>
#define uchar unsigned char
#define uint unsigned int
sbit dula=P2^6;
sbit wela=P2^7;
sbit rs=P3^5;
sbit RW=P3^6;
sbit lcden=P3^4;
sbit key1=P3^0;
sbit key2=P3^1;
sbit key3=P3^2;
sbit rd=P3^7;
uchar code table[]=" 2022-04-28 WED";
uchar code table1[]=" 09:59:50";
uchar count,key1num;
char shi,fen,miao;
void write_sfm(uchar add,uchar date);
void delay(uint xms)
{
uint i,j;
for(i=xms;i>0;i--);
for(j=110;j>0;j--);
}
void write_com(uchar com)
{
rs=0;
RW=0;
lcden=0;
P0=com;
delay(5);
lcden=1;
delay(5);
lcden=0;
}
void write_date(uchar date)
{
rs=1;
RW=0;
lcden=0;
P0=date;
delay(5);
lcden=1;
delay(5);
lcden=0;
}
void LCDINIT()
{
uchar num;
dula=0;
wela=0;
lcden=0;
write_com(0x38);
write_com(0x0c);
write_com(0x06);
write_com(0x01);
write_com(0x80);
for(num=0;num<15;num++)
{
write_date(table[num]);
delay(5);
}
write_com(0x80+0x40);
for(num=0;num<12;num++)
{
write_date(table1[num]);
delay(5);
}
}
void INIT()
{
TMOD=0x01;
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
EA=1;
ET0=1;
TR0=1;
}
void keyscan()
{
rd=0;
if(key1==0)
{
delay(5);
if(key1==0)
{
key1num++;
while(!key1);
//key1num++;
if(key1num==1)
{
TR0=0;
write_com(0x80+0x40+11);
write_com(0x0f);
}
if(key1num==2)
{
TR0=0;
write_com(0x80+0x40+8);
write_com(0x0f);//1a±êéá˸
}
if(key1num==3)
{
TR0=0;
write_com(0x80+0x40+5);
write_com(0x0f);
}
if(key1num==4)
{
key1num=0;
TR0=1;
//write_com(0x80+0x40+11);
write_com(0x0c);
}
}
}
//else
if(key1num!=0)
{
if(key2==0)
{
delay(5);
if(key2==0)
{
while(!key2);
if(key1num==1)
{
miao++;
if(miao==60)
{
miao=0;
}
write_com(0x80+0x40+10);
write_sfm(10,miao);
}
if(key1num==2)
{
fen++;
if(fen==60)
fen=0;
write_sfm(7,fen);
write_com(0x80+0x40+7);
}
if(key1num==3)
{
shi++;
if(shi==24)
shi=0;
write_sfm(4,shi);
write_com(0x80+0x40+4);
}
}
}
if(key3==0)
{
delay(5);
if(key3==0)
{
while(!key3);
if(key1num==1)
{
/*miao--;
if(miao==0)
{
miao=59;
write_sfm(10,miao);
write_com(0x80+0x40+10);
}*/
miao--;
if(miao==-1)
{
miao=59;
write_sfm(10,miao);
write_com(0x80+0x40+10);
}
}
if(key1num==2)
{
fen--;
if(fen==-1)
fen=59;
write_sfm(7,fen);
write_com(0x80+0x40+7);
}
if(key1num==3)
{
shi--;
if(shi==-1)
shi=23;
write_sfm(4,shi);
write_com(0x80+0x40+4);
}
}
}
}
}
//}
//}
void write_sfm(uchar add,uchar date)
{
uchar shi,ge;
shi=date/10;
ge=date%10;
write_com(0x80+0x40+add);
write_date(0x30+shi);
write_date(0x30+ge);
}
void main()
{
LCDINIT();
INIT();
while(1)
{
keyscan();
}
//while(1);
}
void time0() interrupt 1
{
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
count++;
if(count==18)
{
count=0;
miao++;
if(miao==60)
{
miao=0;
fen++;
if(fen==60)
{
fen=0;
shi++;
if(shi==24)
{
shi=0;
}
write_sfm(4,shi);
}
write_sfm(7,fen);
}
write_sfm(10,miao);
}
}
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