真正的万能红外学习与发射单片机程序

ID:773929 · 发表于 2023-8-9 11:23

无需外围38KHZ晶振，STC8H系列芯片按道理都能用，万能接受，万能发射，EEPROM存储数据，暂时只能存一个码，串口输出信息，按下遥控器按键，发送02可显示刚刚收到的信息并保存，发送10可发射刚刚保存的数据，本人新手，程序有些乱，但有注释，因为刚刚做出来所以并不完善，还请大佬多多指教！
红外发射接P11，接受接P20。
原始波形:

经过学以后发射的波形:

单片机源程序如下:

#include "stc8H.h"
#include "intrins.h"
#include <stdio.h>
#include "uart.h"
#include "eeprom.h"
#include "launch.h"
extern char ch;
int ir1 = 0x0400;
unsigned short xdata captures[VAL] = {0},eep_captures[VAL] = {0}; //缓存数组
static unsigned int num = 0; //一共接受了几个脉冲
unsigned int two_num;
static unsigned int Overflow = 0; //溢出次数
static unsigned char val; //接收超时变量
void Timer0_Init(void) //1毫秒@24.000MHz，定时器0
{
AUXR |= 0x80;
TMOD &= 0xF0; //设置定时器模式
// TL0 = 0x90; //设置定时初始值
// TH0 = 0xE8; //设置定时初始值
TL0 = 0x40; //设置定时初始值
TH0 = 0xA2; //设置定时初始值
TF0 = 0; //清除TF0标志
TR0 = 1; //定时器0开始计时
ET0 = 1;
}
void IR() //初始化
{
P1M0 = 0x00;
P1M1 = 0x00;
P3M0 = 0x00;
P3M1 = 0x00;
P5M0 = 0x00;
P5M1 = 0x00;
P_SW2 = 0x80;
PWM1_PS = 0x05;
//(CC1捕获TI1上升沿,CC2捕获TI1下降沿)
PWMA_CCER1 = 0x00;
PWMA_CCMR1 = 0x01; //CC1为输入模式,且映射到TI1FP1上
PWMA_CCMR2 = 0x02; //CC2为输入模式,且映射到TI1FP2上
PWMA_CCER1 = 0x11; //使能CC1/CC2上的捕获功能
PWMA_CCER1 |= 0x00; //设置捕获极性为CC1的上升沿
PWMA_CCER1 |= 0x20; //设置捕获极性为CC2的下降沿
PWMA_CR1 = 0x01;
PWMA_PSCR = 0x09;
PWMA_IER = 0x04; //使能CC2捕获中断
PWMA_IER |= 0x02; //使能CC1捕获中断
EA = 1;
}
void PWMA_ISR() interrupt 26 //PWM沿触发中断
{
unsigned int cnt_l;
unsigned int cnt_h;
if (PWMA_SR1 & 0x02)
{
PWMA_SR1 &= ~0x02;
cnt_l = (PWMA_CCR1 - PWMA_CCR2)/24; //差值即为低电平宽度 cnt/时钟频率 = 脉宽(us)
captures[num++] = cnt_l;
}
if (PWMA_SR1 & 0x04)
{
PWMA_SR1 &= ~0x04;
cnt_h = (PWMA_CCR2 - PWMA_CCR1)/24; //差值即为高电平宽度
captures[num++] = cnt_h;
}
}
void TM0_Isr() interrupt 1 //定时器0中断用来判断脉冲接受是否超时，大于30ms为超时
{
if(P20 == 1)
{
val++;
if(val > 30)
{
Overflow = 1;
val = 0;
}
}else {val = 0;Overflow = 0;}
}
void UartReceiveHandler() interrupt 4 {
if (RI) { // 接收中断
RI = 0; // 清除接收标志位
ch = SBUF; // 读取接收到的数据
//UartSend(ch); // 原样返回接收到的数据
}
}
void TM3_Isr() interrupt 19 //定时器3中断发生38K载波
{
P11 = !P11; //红外1端口
}
//---------------------------------------------------------------------------------------------
void main()
{
unsigned int i = 0,a = 0;
Timer0_Init();
Timer3_Init();
UartInit();
IR();
UartSendString("Starting\r\n");
lach1 = 1;
while(1)
{
//lach1 = 1;
if(Overflow == 1 && ch == 0x02)//如果超时溢出,并且接收到0x02
{
EraseUIntFromEEPROM(0x0400);
EraseUIntFromEEPROM(0x0600);
delays(5);
EraseUIntFromEEPROM(0x0000);
delays(5);
for(i = 0; i <= num; i++)
{
SaveUIntToEEPROM(ir1+i*2, captures[i]); //写入eeprom
//SaveUIntToEEPROM(ir1+i*2, '3'); //写入eeprom
UartSendUint(captures[i]);//打印保存到数组里的数据
captures[i] = 0;
delays(1);
}
SaveUIntToEEPROM(0x0000, num); //将脉冲个数写入eeprom
UartSendString("End\r\n"); /*End结束*/
UartSendUint(num);
ir1 = 0x0400;
ch = 0;
num = 0;
Overflow = 0;
PWMA_IER = 0; //关闭PWM中断使能
ET0 = 0; //关闭定时器0中断
}else if(P20 == 0 && Overflow==0){
PWMA_IER = 0x06; //打开PWM中断使能
ET0 = 1; //打开定时器0中断
}
if(ch == 0x01)
{
two_num = ReadUIntFromEEPROM(0x0000);
for(a = 0;a<=two_num;a++) //读取红外接收数组
{
eep_captures[a] = ReadUIntFromEEPROM(ir1+a*2);
UartSendUint(eep_captures[a]);//打印保存到数组里的数据
delays(1);
}
UartSendUint(two_num);
ir1 = 0x0400;
two_num = 0;
ch = 0x00;
}
if(ch == 0x10)
{
two_num = ReadUIntFromEEPROM(0x0000);
for(a = 0;a<=two_num;a++) //读取红外接收数组
{
eep_captures[a] = ReadUIntFromEEPROM(ir1+a*2);
UartSendUint(eep_captures[a]);//打印保存到数组里的数据
delays(1);
}
Launch_1(eep_captures,two_num);
ch = 0;
}
}
}
单片机源程序如下:
[code]#include "stc8H.h"
#include "intrins.h"
#include <stdio.h>
#include "uart.h"
#include "eeprom.h"
#include "launch.h"
extern char ch;
int ir1 = 0x0400;
unsigned short xdata captures[VAL] = {0},eep_captures[VAL] = {0}; //缓存数组
static unsigned int num = 0; //一共接受了几个脉冲
unsigned int two_num;
static unsigned int Overflow = 0; //溢出次数
static unsigned char val; //接收超时变量
void Timer0_Init(void) //1毫秒@24.000MHz，定时器0
{
AUXR |= 0x80;
TMOD &= 0xF0; //设置定时器模式
// TL0 = 0x90; //设置定时初始值
// TH0 = 0xE8; //设置定时初始值
TL0 = 0x40; //设置定时初始值
TH0 = 0xA2; //设置定时初始值
TF0 = 0; //清除TF0标志
TR0 = 1; //定时器0开始计时
ET0 = 1;
}
void IR() //初始化
{
P1M0 = 0x00;
P1M1 = 0x00;
P3M0 = 0x00;
P3M1 = 0x00;
P5M0 = 0x00;
P5M1 = 0x00;
P_SW2 = 0x80;
PWM1_PS = 0x05;
//(CC1捕获TI1上升沿,CC2捕获TI1下降沿)
PWMA_CCER1 = 0x00;
PWMA_CCMR1 = 0x01; //CC1为输入模式,且映射到TI1FP1上
PWMA_CCMR2 = 0x02; //CC2为输入模式,且映射到TI1FP2上
PWMA_CCER1 = 0x11; //使能CC1/CC2上的捕获功能
PWMA_CCER1 |= 0x00; //设置捕获极性为CC1的上升沿
PWMA_CCER1 |= 0x20; //设置捕获极性为CC2的下降沿
PWMA_CR1 = 0x01;
PWMA_PSCR = 0x09;
PWMA_IER = 0x04; //使能CC2捕获中断
PWMA_IER |= 0x02; //使能CC1捕获中断
EA = 1;
}
void PWMA_ISR() interrupt 26 //PWM沿触发中断
{
unsigned int cnt_l;
unsigned int cnt_h;
if (PWMA_SR1 & 0x02)
{
PWMA_SR1 &= ~0x02;
cnt_l = (PWMA_CCR1 - PWMA_CCR2)/24; //差值即为低电平宽度 cnt/时钟频率 = 脉宽(us)
captures[num++] = cnt_l;
}
if (PWMA_SR1 & 0x04)
{
PWMA_SR1 &= ~0x04;
cnt_h = (PWMA_CCR2 - PWMA_CCR1)/24; //差值即为高电平宽度
captures[num++] = cnt_h;
}
}
void TM0_Isr() interrupt 1 //定时器0中断用来判断脉冲接受是否超时，大于30ms为超时
{
if(P20 == 1)
{
val++;
if(val > 30)
{
Overflow = 1;
val = 0;
}
}else {val = 0;Overflow = 0;}
}
void UartReceiveHandler() interrupt 4 {
if (RI) { // 接收中断
RI = 0; // 清除接收标志位
ch = SBUF; // 读取接收到的数据
//UartSend(ch); // 原样返回接收到的数据
}
}
void TM3_Isr() interrupt 19 //定时器3中断发生38K载波
{
P11 = !P11; //红外1端口
}
//---------------------------------------------------------------------------------------------
void main()
{
unsigned int i = 0,a = 0;
Timer0_Init();
Timer3_Init();
UartInit();
IR();
UartSendString("Starting\r\n");
lach1 = 1;
while(1)
{
//lach1 = 1;
if(Overflow == 1 && ch == 0x02)//如果超时溢出,并且接收到0x02
{
EraseUIntFromEEPROM(0x0400);
EraseUIntFromEEPROM(0x0600);
delays(5);
EraseUIntFromEEPROM(0x0000);
delays(5);
for(i = 0; i <= num; i++)
{
SaveUIntToEEPROM(ir1+i*2, captures[i]); //写入eeprom
//SaveUIntToEEPROM(ir1+i*2, '3'); //写入eeprom
UartSendUint(captures[i]);//打印保存到数组里的数据
captures[i] = 0;
delays(1);
}
SaveUIntToEEPROM(0x0000, num); //将脉冲个数写入eeprom
UartSendString("End\r\n"); /*End结束*/
UartSendUint(num);
ir1 = 0x0400;
ch = 0;
num = 0;
Overflow = 0;
PWMA_IER = 0; //关闭PWM中断使能
ET0 = 0; //关闭定时器0中断
}else if(P20 == 0 && Overflow==0){
PWMA_IER = 0x06; //打开PWM中断使能
ET0 = 1; //打开定时器0中断
}
if(ch == 0x01)
{
two_num = ReadUIntFromEEPROM(0x0000);
for(a = 0;a<=two_num;a++) //读取红外接收数组
{
eep_captures[a] = ReadUIntFromEEPROM(ir1+a*2);
UartSendUint(eep_captures[a]);//打印保存到数组里的数据
delays(1);
}
UartSendUint(two_num);
ir1 = 0x0400;
two_num = 0;
ch = 0x00;
}
if(ch == 0x10)
{
two_num = ReadUIntFromEEPROM(0x0000);
for(a = 0;a<=two_num;a++) //读取红外接收数组
{
eep_captures[a] = ReadUIntFromEEPROM(ir1+a*2);
UartSendUint(eep_captures[a]);//打印保存到数组里的数据
delays(1);
}
Launch_1(eep_captures,two_num);
ch = 0;
}
}
}

复制代码

原理图:无
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程序:

8路红外.zip (125.01 KB, 下载次数: 64)

ID:433219 · 发表于 2023-8-9 16:32

，发送02可显 --->pc上，stc-isp软件向mcu串口发送？？？

ID:276663 · 发表于 2023-8-9 17:41

实物靓照呢

ID:773929 · 发表于 2023-8-10 08:43

wkman 发表于 2023-8-9 16:32
，发送02可显 --->pc上，stc-isp软件向mcu串口发送？？？

向mcu发

ID:773929 · 发表于 2023-8-10 08:47

IdeaMing 发表于 2023-8-9 17:41
实物靓照呢

才刚调好一路，板子焊接的烂，没好意思发

ID:276663 · 发表于 2023-8-10 11:06

范莉萍发表于 2023-8-10 08:47
才刚调好一路，板子焊接的烂，没好意思发

现在学习型遥控器只要一个发射灯就能实现学习了，有没有搞清楚原理

ID:773929 · 发表于 2023-8-10 11:50

IdeaMing 发表于 2023-8-10 11:06
现在学习型遥控器只要一个发射灯就能实现学习了，有没有搞清楚原理

8路发射对应的是8个位置，比如八间屋子

ID:256970 · 发表于 2023-8-10 14:45

IdeaMing 发表于 2023-8-10 11:06
现在学习型遥控器只要一个发射灯就能实现学习了，有没有搞清楚原理

发射头是可以接收的，只是接收到的信号较弱，只能近距离接收

ID:773929 · 发表于 2023-8-10 15:36

蓝色海阳发表于 2023-8-10 14:45
发射头是可以接收的，只是接收到的信号较弱，只能近距离接收

啊？这么吊

ID:1099505 · 发表于 2024-3-12 07:24

真不错，学习了。

ID:235438 · 发表于 2024-3-20 00:21

我都用定时器来做,还不会用捕获,代码收了,回头试试看

ID:777254 · 发表于 2025-2-27 16:48

楼主做完万能学习型红外方案了吗？可不可以指导一下，不白嫖

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真正的万能红外学习与发射 单片机程序

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真正的万能红外学习与发射单片机程序