怎么整合这两个程序，本人初学者，大神帮忙啊

ID:59174 · 发表于 2014-2-19 15:05

我想要实现蜂鸣器和点阵的同时工作，蜂鸣器工作，点阵显示字，每一个分开运行都没问题，但我想让他们同时工作，我觉得应该是中断冲突，大神们给点指点吧。。不胜感激。。。
蜂鸣器程序

#include <REG51.H>

#define uchar unsigned char

sbit beepIO=P1^5;

uchar m,n;

uchar code T[49][2]={{0,0},

{0xF8,0x8B},{0xF8,0xF2},{0xF9,0x5B},{0xF9,0xB7},{0xFA,0x14},{0xFA,0x66},{0xFA,0xB9},{0xFB,0x03},{0xFB,0x4A},{0xFB,0x8F},{0xFB,0xCF},{0xFC,0x0B},

{0xFC,0x43},{0xFC,0x78},{0xFC,0xAB},{0xFC,0xDB},{0xFD,0x08},{0xFD,0x33},{0xFD,0x5B},{0xFD,0x81},{0xFD,0xA5},{0xFD,0xC7},{0xFD,0xE7},{0xFE,0x05},

{0xFE,0x21},{0xFE,0x3C},{0xFE,0x55},{0xFE,0x6D},{0xFE,0x84},{0xFE,0x99},{0xFE,0xAD},{0xFE,0xC0},{0xFE,0x02},{0xFE,0xE3},{0xFE,0xF3},{0xFF,0x02},

{0xFF,0x10},{0xFF,0x1D},{0xFF,0x2A},{0xFF,0x36},{0xFF,0x42},{0xFF,0x4C},{0xFF,0x56},{0xFF,0x60},{0xFF,0x69},{0xFF,0x71},{0xFF,0x79},{0xFF,0x81}

};

uchar code music[][2]={{0,4},

{14,2},{14,2},{16,8},{14,8},{19,8},{18,8},{0,8},{14,4},{14,4},{16,8},{14,8},{21,8},{19,8},{0,8},{14,4},{14,4},{26,8},{23,8},{19,8},{18,8},{29,10},{24,4},{24,4},{23,8},{19,8},{21,8},{23,8},

{0xFF,0xFF}};

void delay(uchar p)

{

uchar i,j;

for(;p>0;p--)

for(i=181;i>0;i--)

for(j=181;j>0;j--);

}

void pause()

{

uchar i,j;

for(i=150;i>0;i--)

for(j=150;j>0;j--);

}

void T0_int() interrupt 1

{

beepIO=!beepIO;

TH0=T[m][0]; TL0=T[m][1];

}

void main()

{

uchar i=0;

TMOD=0x01; EA=1; ET0=1;

while(1)

{

m=music[0];n=music[1];

if(m==0x00)

{TR0=0;delay(n);i++;}

else if(m==0xFF)

{TR0=0;delay(30);i=0;}

else if(m==music[i+1][0])

{TR0=1;delay(n);TR0=0;pause();i++;}

else

{TR0=1;delay(n);i++;}

}

ID:59174 · 发表于 2014-2-19 15:06

这个是点阵的程序

#include <reg52.h>
#include "74hc595.h"
/********************************定义变量和数组********************************/
unsigned char code table[] = {0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f,};
unsigned char code Digit_Tab[9][8] = {
{0x0C,0x06,0xCC,0x80,0x80,0xCC,0x06,0x0C}, //字模取模方式阴码逆向逐列式
{0x92,0x92,0xFE,0x00,0xFE,0x92,0x92,0xFE},/*"0",0*/

{0x10,0x90,0x7E,0x12,0x9A,0xFE,0x10,0x10},/*"未命名文件",0*/

{0x08,0x84,0x86,0x94,0xFF,0x94,0x84,0x80},/*"1",1*/

{0x00,0x00,0xFE,0x92,0x92,0xFE,0x00,0x00},/*"2",2*/

{0x38,0xFE,0x90,0xD4,0x7F,0x54,0xDC,0x90},/*"3",3*/

{0x00,0x4C,0x2A,0x89,0xFC,0x08,0x28,0x40},/*"4",4*/

};
unsigned int count;
unsigned char cnta;
unsigned char cntb;
/******************************************************************************/
/* 函数名称  : Timer0                                                       */
/* 函数描述  : T0中断函数                                                    */
/* 输入参数  : 无                                                          */
/* 参数描述  : 无                                                          */
/* 返回值 : 无                                                          */
/******************************************************************************/
void Timer0(void) interrupt 1 using 0
{
TH0 = (65536 - 1200) / 256;
TL0 = (65536 - 1200) % 256;
      Ser_IN(table[cnta]);                //8X8点阵列扫描
      Ser_IN(Digit_Tab[cntb][cnta]);    //8X8点阵行送扫描数据
      Par_OUT();                         //74HC595输出显示
cnta++;
if(cnta == 8)
{
      cnta = 0;
}
count++;
if(count == 1200)
{
      count = 0;
      cntb++;
      if(cntb == 7)
      {
         cntb = 0;
      }
}
}
/******************************************************************************/
/* 函数名称  : main                                                          */
/* 函数描述  : 主函数                                                       */
/* 输入参数  : 无                                                          */
/* 参数描述  : 无                                                          */
/* 返回值 : 无                                                          */
/******************************************************************************/
void main(void)
{
TMOD = 0x01;
TH0 = (65536-1000) / 256;
TL0 = (65536-1000) % 256;
TR0 = 1;
ET0 = 1;
EA=1;
while(1)
{
      ;
}
}

ID:7485 · 发表于 2014-2-23 12:14

蜂鸣器采用定时器中断（输出口翻转）即可。

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