#include <avr/wdt.h>
const int ledPin = 13; // the number of the LED pin
void setup() {
wdt_disable();
Serial.begin(9600);
Serial.println("System Init OK!");
pinMode(ledPin, OUTPUT);
Serial.println("Wait 5 Sec..");
delay(5000);
wdt_enable(WDTO_8S);
Serial.println("Watchdog enabled!");
}
uint8_t timer = 0;
void loop() {
if (!(millis() % 1000)) {
Serial.print(millis());
Serial.print("--");
timer++;
Serial.println(timer);
digitalWrite(ledPin, digitalRead(ledPin) == 1 ? 0 : 1); delay(1);
}
// wdt_reset();
}
这个程序无法正常复位，13引脚的灯一直闪烁。帖子里有人用了：
解决方案：http://www.nongnu.org/avr-libc/u ... _avr__watchdog.html
这里的说明： Note that for newer devices (ATmega88 and newer, effectively any AVR that has the option to also generate interrupts), the watchdog timer remains active even after a system reset (except a power-on condition), using the fastest prescaler value (approximately 15 ms). It is therefore required to turn off the watchdog early during program startup, the datasheet recommends a sequence like the following: 对于atmega88以及新型号的单片机(自带产生中断的），看门狗可能会在系统复位之后，依然运行(除掉电复位外）。因此，需要在程序启动早期，关闭看门狗。datasheet中推荐插入一段这样的程序:
#include <stdint.h>
#include <avr/wdt.h>
uint8_t mcusr_mirror __attribute__ ((section (".noinit")));
void get_mcusr(void) \
__attribute__((naked)) \
__attribute__((section(".init3")));
void get_mcusr(void)
{
mcusr_mirror = MCUSR;
MCUSR = 0;
wdt_disable();
}
但是这段程序我加了好几个位置都不行，还是不断地复位，等反复闪烁，哪位大神能狗解决这个问题？
|
