哎!这些日子发生了很多事,很多人让我改变看法,也许我也是有点。。。。
真是很郁闷,真的还好有它---------给我挑战,给我动力,加油!努力!
这是我一贯的,用笨法子编程,管他那,能用就行 啊!
128*64的半屏和刷屏程序!
#include<reg51.h>
#define uint unsigned int;
#define uchar unsigned char;
sbit rs=P1^0;//并行模式下为指令数据选择信H/L=指令/数据
虽然并不是什么图,只是很多点,但是我知道他意味这什么,
第一幅是在PC上显示的图,第二幅是在12864液晶上显示的图,也就是如果我ROM足够大,我可以做视屏,这一点我坚信!只是现在我的ROM存储到没有了,所以ROM空间放不下了,我才用了半屏。现在要大ROM也是很简单的,16K的,64K的,多了,只要有钱!呵呵


- sbit rw=P1^1;//并行的读写信号H/L=读/写
- sbit e=P1^2; //并行下的使能信号
- sbit reset=P1^5;
- uchar x,y;//坐标
- uchar datetabal;
- uchar d1,d2;//数据缓冲
- uchar k=0,h=0;
- unsigned int i,j;
- uchar code tab[]={/*-- 调入了一幅图像:C:\Users\lenovo\Desktop\100001313985056.bmp --*/
- /*-- 宽度x高度=128x32 --*/
- 0x00,0x00,0x00,0x00,0x00,0x00,0x3C,0x0C,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x00,0x00,0x0F,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0xFF,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x00,0x00,0xE1,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x00,0x00,0x1F,0xF0,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x3F,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x00,0x00,0xC7,0x30,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x00,0x00,0x1F,0xFF,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x66,0x4A,0xFC,0xEF,0xF5,0x92,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0xC6,0x0F,0x99,0x49,0x9D,0x5F,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x8D,0xFD,0x66,0x79,0x67,0x4D,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x19,0x3E,0x96,0x8F,0xCB,0xA9,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x33,0xE9,0xF2,0x60,0xB6,0xFB,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0xE7,0xD3,0xFF,0x33,0xED,0xC6,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x4F,0x4E,0x33,0x93,0x33,0x64,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x7E,0xA6,0xCC,0xD8,0x42,0xAD,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x4C,0x34,0x48,0x46,0x00,0x2A,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x93,0x7E,0x36,0xE9,0xFF,0x64,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x57,0xFF,0xCA,0x26,0x00,0xBB,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0xBF,0x4D,0xF1,0x78,0x00,0x2D,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x38,0x05,0xAC,0x73,0xFF,0xFE,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0xFD,0xB4,0xBE,0xBE,0x00,0x29,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x32,0xB6,0x4F,0xF5,0xFF,0x6C,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0xF6,0x0A,0x6B,0xAA,0x00,0x52,0x00,0x00,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x7D,0x4A,0x3E,0x6D,0x9B,0xD5,0x8A,0x45,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0xBF,0xAF,0xCC,0xF6,0x50,0x6C,0x77,0xA8,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x76,0x15,0xAF,0x7A,0xAB,0xA7,0x6A,0x13,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x5D,0xAA,0x7F,0xFE,0x5D,0xFF,0x4D,0xD4,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0xEC,0x25,0xB3,0xB8,0x5B,0xCF,0xEC,0x2D,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x6F,0xDE,0xB6,0x65,0xFF,0x27,0xF7,0xFC,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0xAB,0x2D,0x73,0x7A,0x3E,0x51,0x29,0x9B,0x00,0x00,0x00,0x00,
- 0x00,0x00,0x00,0x00,0x4B,0xC5,0x5D,0xF3,0xFD,0x4D,0xFC,0xCE,0x00,0x00,0x00,0x00,
- };
- void delay40ms(void) //误差 -0.000000000009us
- {
- unsigned char ad,bd,cd;
- for(cd=11;cd>0;cd--)
- for(bd=124;bd>0;bd--)
- for(ad=12;ad>0;ad--);
- }
- void delay4_6ms()//
- {
- unsigned char av,bv;
- for(bv=12;bv>0;bv--)
- for(av=175;av>0;av--);
- }
- void delay(void)
- {
- ;;;
- }
- void writedate(unsigned char a)//写数据
- {
-
-
-
- delay4_6ms();
- rs=1;
- delay();
- rw=0;
- delay();
- e=1;
- delay();
- P0=a;
-
-
-
- delay();
- e=0;
- delay();
-
-
- }
- void writectrl(unsigned char ds)//写指令
- {
- rs=0;
- delay();
- rw=0;
- delay();
- e=1;
- delay();
- P0=ds;
- delay();
- e=0;
- delay();
-
- }
- void main()
- {
- reset=0;
- delay();
- reset=1;
- delay40ms();
- writectrl(0x3f);//开扩充指令操作数据位选择8位
- delay4_6ms();
-
- writectrl(0x3e);//写指令扩充指令操作,8位数据,绘图开关关
- delay4_6ms();
- // writectrl(0x80);//写指令设置 垂直 列地址 Y轴为 “0”
- //delay4_6ms();
- //writectrl(0x80);//写指令设置 水平 行地址 X轴 “0”
- //delay4_6ms();
- //writedate(0xffff); //数据写入FffFH
- //delay4_6ms();
- x=0;
- y=0;
- i=0;
- j=0;
- for( h=0;h<32;h++ )
- {
- x=0;
- for (k=0;k<8;k++)
- {
-
-
- writectrl((0x80+y));//写指令设置 垂直 列地址 Y轴为 “0”
- delay4_6ms();
- writectrl((0x80+x));//写指令设置 水平 行地址 X轴 “0”
- delay4_6ms();
- writedate(tab[i]); //数据写入FFH
- i++;
- writedate(tab[i]); //数据写入FFH
- delay4_6ms();
- i++;
-
- x++;
-
- }
- y++;
-
-
-
-
- }
- //;***********以上是上半屏(Y=0-1F,X=0-07)以下是下扳平Y=8-0F X=0-1F********************************
- x=0;y=0;
- for( h=0;h<32;h++ )
- {
- x=0;
- for (k=0;k<8;k++)
- {
-
-
- writectrl((0x80+y));/:/写指令设置 垂直 列地址 Y轴为 “0”
- delay4_6ms();
- writectrl((0x88+x));//写指令设置 水平 行地址 X轴 “0”
- delay4_6ms();
- writedate(0x00); //数据写入FFH
- i++;
- writedate(0x00); //数据写入FFH
-
- delay4_6ms();
- i++;
- x++;
-
- }
- y++;
-
-
-
-
- }
-
-
-
- while(1); //*******************************************************
- //12864到今晚我也成功了,呵呵,我是这样的:把12864分成两部分,上半部分12832,下半部分12832
- //然后用扫描的办法从第一行开始扫描,知道32行,在执行下半部分扫描程序,第33行开始,扫描32行道64至
- //这里还要说一个事:关于12864画图,你看那大海,水很多,但是它是由一滴滴水组成的,所以要想在12864屏幕上显示一幅图像,你就要
- //从一个点开始,第一步我让第一行的第一列显示一个点,怎么实现呢?我开始很是不明白,看了一天的手册,一下午的实验,终于总结出
- //1:向7920的写入3F和3E指令,使液晶工作在扩展指令状态,8位数据,绘图开关开2:设定绘图RAM地址,先写入列(Y轴)再写入行(X轴)
- //然后再一口气写入16位的数据,也可以写8位,但要写2次,我是采取后者,然后这十六是什么呢?---即这样的排列D15-D0,让第一个点就写入8000H
- //那么,现在就是在第一行第一列显示一个点!呵呵,会写一个点,你就一定会写一幅图像了,为什么呢,你只要让单片机这样重复的写512个字就是有一幅
- //12864的图像了,这其实说白了就是点阵啊----------
-
- //呵呵,2010年11月17日 与天津开发区第四项目部宿舍,操今天给分包队干了一天的活,很郁闷,但是有单片机真的让我开心起来
- //
- //
- //
- //
- //
- //
- //
- ///
- //***************************************************8
- }
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