共阴极数码管0-99动态显示，

ID:202137 · 发表于 2017-5-22 13:09

求大神解答，共阴极数码管0-99动态显示，循环1次，只用两个数码管！跪求！！！！

ID:149988 · 发表于 2017-5-22 18:56

不知是否符合要求，你可参考一下：
#include<reg51.h> //包含特殊功能寄存器头文件
#include<intrins.h>
#define uint unsigned int    //定义uint=unsigned int
#define uchar unsigned char //定义uchar=unsigned char
#define wela P1    //位选
#define dula P0    //段选
uchar code we_code[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f}; //位码表
uint code du_code[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71}; //段码表
void delayms(uint xms);
uchar temp,t0,t1,bai,shi,ge;
uint shu;
void init();
void display(uchar aa,uchar bb,uchar cc,uchar bai,uchar shi,uchar ge);
void delayms(uint xms)
  {
uint i,j;
for(i=xms;i>0;i--) //i=xms即延时约xms毫秒
{
   for(j=110;j>0;j--);
}
}
void main()
{
  init();
while(1)
{
display(7,6,5, bai, shi, ge);
}
}
void init()
{
shu=999;
temp=0xfe;
P0=temp;
TMOD=0x11;
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
TH1=(65536-50000)/256;
TL1=(65536-50000)%256;
EA=1;
ET0=1;
ET1=1;
TR0=1;             //初始化子程序，初始化专用关键字
TR1=1;
}
void timer0() interrupt 1
{
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
t0++;
if(t0==20)
{
t0=1;
temp=_crol_(temp,1);
P0=temp;
}
}
void timer1() interrupt 3
{
TH1=(65536-50000)/256;
TL1=(65536-50000)%256;
t1++;
if(t1==4)
{
t1=0;
shu --;
bai=shu/100;
shi=shu%100/10;
ge=shu%10;
if(shu==888)
{
TR0=0;
TR1=0;
}
}
}
void display(uchar aa,uchar bb,uchar cc,uchar bai,uchar shi,uchar ge)
{
dula=du_code[aa];
wela=we_code[1];
delayms(5);
dula=du_code[bb];
wela=we_code[2];
delayms(5);
dula=du_code[cc];
wela=we_code[3];
delayms(5);
// dula=du_code[qian];
// wela=we_code[4];
// delayms(5);
dula=du_code[bai];
wela=we_code[4];
delayms(5);
dula=du_code[shi];
wela=we_code[5];
delayms(5);
dula=du_code[ge];
wela=we_code[6];
delayms(5);
}

ID:202137 · 发表于 2017-5-22 23:26

不倒翁.WZT 发表于 2017-5-22 18:56
不知是否符合要求，你可参考一下：
#include //包含特殊功能寄存器头文件
#include

非常感谢，明天就试一试

ID:203734 · 发表于 2017-5-23 08:48

#include<reg52.h>
#define uchar unsigned char
#define uint unsigned int
uchar ge;
uint tt;
//unsigned char led_seg[]={0x03,0x9f,0x25,0x0d,0x99,0x49,0x41,0x1f,0x01,0x09,0xfd,0xc1,0x63,0x85,0x61,0x71}; //共阳
//unsigned char led_bit[]={0x80,0x40,0x20,0x10,0x08,0x04,0x02,0x01};
unsigned char led_seg[]={0xfc,0x60,0xda,0xf2,0x66,0xb6,0xbe,0xe0,0xfe,0xe6};
unsigned char led_bit[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};    //共阴
sbit SH_CP=P2^4;
sbit ST_CP=P1^5;
sbit DS=P2^5;
uchar d;

void write(uchar d)                            //定义输入函数
{
uchar i;
for(i=0;i<8;i++)
{
DS=d&0x01;
SH_CP=1;
SH_CP=0;
d=d>>1;
}
}

void init()                            //定义重置函数
{
SH_CP=0;
ST_CP=0;
DS=0;
write(0);
write(0);
ST_CP=1;
ST_CP=0;
}

void delay(uint z)                            //延迟函数
{
uint x,y;
for(x=z;x>0;x--)
for(y=110;y>0;y--);
}

void display(uchar x)
{

write(led_seg[x/10]);
delay(1);
write(led_bit[6]);
ST_CP=1;
ST_CP=0;

write(led_seg[x%10]);
delay(1);
write(led_bit[7]);
ST_CP=1;
ST_CP=0;
} //显示秒钟

void main()
{
init();
TMOD=0x01;
// TH0=(65536-18432)/256;
// TL0=(65536-18432)%256;
EA=1;
ET0=1;
TR0=1;
while(1)
{
display(ge);
}
}

void exter0() interrupt 1 // 定时器1中断
{
// TH1=(65536-18432)/256;
// TL1=(65536-18432)%256;
tt++;
if(tt==28)
{
tt=0;
ge++;
if(ge==60)
{
ge=0;

}
      }
}

我这是0到59的，你改下试试看

ID:490252 · 发表于 2019-3-13 20:28

15281728234 发表于 2017-5-22 23:26
非常感谢，明天就试一试

为什么一个都不亮啊

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共阴极数码管0-99动态显示，

RE: 共阴极数码管0-99动态显示，