逆向解析单片机串口校验算法,帧尾FC的前2个字节是怎么算出来的?

帮忙解析一下串口校验算法,看看帧尾FC的前2个是怎么算出来的，以下是单片机发出来的数据：
FD 88 01 01 00 00 00 00 00 00 00 8B 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 16 91 FC
FD 88 01 01 04 00 00 00 00 00 00 8B 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 CA 9D FC
FD 88 01 01 08 00 00 00 00 00 00 8B 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 BE A8 FC
FD 88 01 01 0C 00 00 00 00 00 00 8B 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 62 A4 FC
FD 88 01 01 04 00 00 00 00 00 00 88 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 FB 00 BB FC
FD 88 01 01 40 00 00 00 00 00 00 8B 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 07 FB 01 FC
FD 88 01 01 04 00 00 00 00 00 00 80 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 7C AB FC

梦想未央 发表于 2021-4-14 09:23
计算参考：【CRC笔记】CRC-16 XMODEM C语言实现  https://blog.csdn.net/u012028275/article/details/11206 ...

采用的是CRC-16/XMODEM校验方式，FD为帧头，不参于校验，数据位从88开始，FC为帧尾，前两位为校验码，高位在前，低位在后

只能胡猜

modbus算法，楼主详细了解一下。

采用的是CRC-16/XMODEM校验方式，FD为帧头，不参于校验，数据位从88开始，FC为帧尾，前两位为校验码，高位在前，低位在后。可以用在线校验查看，网址为：见下图

计算参考：【CRC笔记】CRC-16 XMODEM C语言实现  https://blog.csdn.net/u012028275/article/details/112067463

应该是crc16 ，反推只能穷举咯。

梦想未央 发表于 2021-4-13 15:50
采用的是CRC-16/XMODEM校验方式，FD为帧头，不参于校验，数据位从88开始，FC为帧尾，前两位为校验码，高 ...

我昨天在网上查到了，也解也来了，是CRC16-CCITT算法，还是谢谢你，分给你了