我把一首歌的歌谱翻译为代码，在ISIS仿真过程中，每当播放到快结束的地方就从头开始了，后面的就没有了，如此循环。经过多次改动试验，我推测是单次循环时间达到上限，请问如何延长单次循环时间，从而实现歌曲的完整播放？（代码见下）（最后有仿真图片）
#include <reg52.h>
#define uchar unsigned char
#define uint unsigned int
sbit fm=P3^4; //蜂鸣器控制端口
uchar timeh,timel; //用于存放定时器的高8位和低8位
uchar code zbjbxf[]={ //定义《快乐成长》的简谱数组
0xB3,0x91,0xC2,0xB6,0x83,0x61,0x92,0x86,0x62,0x61,0x61,0x62,0x82,0x81,0x81,0x82,0x92,0x82,0x42,0x56, //歌曲第一段（与歌谱每行对应，至反复记号处）
0x62,0x02,0x42,0x64,0x82,0xB2,0xA2,0x82,0x96,0x94,0xB1,0x91,0x84,0x91,0x81,0x12,0x82,0x51,0x61,0x4A,
0x62,0x84,0x42,0x93,0x81,0x61,0x51,0x42,0x52,0x62,0x14,0x12,0x23,0x11,0x81,0x91,0x82,0x02,0x61,0x61,
0x92,0x82,0x42,0x56,0x62,0x02,0x42,0x64,0x41,0x81,0xB4,0xA2,0x83,0x91,0x82,0x53,0x41,0x51,0x61,0x26,
0x44,0x72,0x94,0x91,0x91,0x84,0x82,0x94,0x62,0x92,0x82,0x32,0x4A,0x81,0x61,0xB2,0xB1,0x91,0xC2,
0xB6,0x82,0x81,0x61,0x92,0x86,0x92,0xB2,0xB2,0xC2,0xB3,0x91,0x62,0x52,0x42,0x12,0x82,0x42,0x56,
0x62,0x02,0x42,0x64,0x82,0xB2,0xA2,0x82,0x96,0x92,0xB3,0x91,0x82,0x92,0x82,0x62,0x52,0x42,0x12,0x82,0x51,0x61,
0x4C,
0xB3,0x91,0xC2,0xB6,0x83,0x61,0x92,0x86,0x62,0x61,0x61,0x62,0x82,0x81,0x81,0x82,0x92,0x82,0x42,0x56, //歌曲第二段（与歌谱每行对应）
0x62,0x02,0x42,0x64,0x82,0xB2,0xA2,0x82,0x96,0x94,0xB1,0x91,0x84,0x91,0x81,0x12,0x82,0x51,0x61,0x4A,
0x62,0x84,0x42,0x93,0x81,0x61,0x51,0x42,0x52,0x62,0x14,0x12,0x23,0x11,0x92,0x82,0x02,0x61,0x61,
0x92,0x82,0x42,0x56,0x62,0x02,0x42,0x64,0x41,0x81,0xB4,0xA2,0x83,0x91,0x82,0x93,0x81,0x81,0x91,0x66,
0x44,0x72,0x94,0x91,0x91,0x84,0x82,0x94,0x62,0x92,0x82,0x32,0x4A,0x81,0x61,0xB2,0xB1,0x91,0xC2,
0xB6,0x82,0x81,0x61,0x92,0x86,0x92,0xB2,0xB2,0xC2,0xB3,0x91,0x62,0x52,0x42,0x12,0x82,0x42,0x56,
0x62,0x02,0x42,0x64,0x82,0xB2,0xA2,0x82,0x96,0x92,0xB3,0x91,0x82,0x92,0x82,0x62,0x52,0x42,0x12,0x82,0x51,0x61,
0x46,0x62,0x02,0x42,0x64,0x82,0xB2,0xA2,0x82,0x9C,
0x92,0xB3,0x91,0x82,0x92,0x82,0x62,0x52,0x42,0x14,0x82,0x94,0x82,0xBC,0xff};
uchar code chuzhi[]={ //适合12M的晶振定时器初值表，高低8位分开
0xff,0xff, //占位
0xFB,0xE9, //D调低音5-中音4
0xFC,0x5B,
0xFC,0xBD,
0xFC,0xED,
0xFD,0x43,
0xFD,0x8E,
0xFD,0xB3,
0xFD,0xF3, //D调中音5-高音4
0xFE,0x2D,
0xFE,0x5E,
0xFE,0x76,
0xFE,0xA1,
0xFE,0xD0,
0xFE,0xD9,
};
void timer0() interrupt 1{ //定时器0中断服务程序
TH0=timeh; //将timeh赋给计时器的高8位
TL0=timel; //将timel赋给计时器的低8位
fm=~fm; //定时器每次到时将蜂鸣器反相
}
void delay(uint z){ //延时238ms,即八分音符
uint y;
for(z;z>0;z--)
for(y=27406;y>0;y--); //大致时间
}
void delay1(uint z){ //音符间适当延时
uint y;
for(z;z>0;z--)
for(y=162;y>0;y--); //大致时间
}
void main(){
uint temp; //存放简谱数组中的每一个音符的临时变量
uchar i=0;
uchar jp; //jp用于取出temp中的高8位和低8位
TMOD=0x01; //设置定时器T0工作于方式1
IE=0x82; //允许T0中断
while(1){
temp=zbjbxf;
if(temp==0xff)
break;
jp=temp/16; //取数的高4位，音频数值
if(jp!=0){
timeh=chuzhi[jp*2]; //构造定时器初值高8位
timel=chuzhi[jp*2+1]; //构造定时器初值低8位
TR0=1; //开定时器
}else{
TR0=0; //关定时器
fm=1; //关蜂鸣器
}
delay(temp%16); //取数的低4位,节拍（音符总时延）
TR0=0; //唱完一个音停5ms
fm=1;
delay1(5);
TR0=1;
i++;
}
TR0=0; //关定时器
fm=1; //关蜂鸣器
}
仿真图片如下：
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