求教！如何把倒计时60s的程序改成“00：00”用4位led显示的2分钟程序

ID:72803 · 发表于 2015-1-26 10:07

下面是倒计时60s的程序
求大神改写

#include<reg51.h>

sbit dula=P2^6;
sbit wela=P2^7;
sbit beep=P2^3;
unsigned char j,k,a1,a0,s=60;
unsigned int m;
unsigned char code table[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,
0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71};

void delay(unsigned char i)
{
for(j=i;j>0;j--)
for(k=125;k>0;k--);
}
void display(unsigned char sh_c,unsigned char g_c)
{
dula=0;
P0=table[sh_c];
dula=1;
dula=0;

wela=0;
P0=0xfe;
wela=1;
wela=0;
delay(5);

P0=table[g_c];
dula=1;
dula=0;

P0=0xfd;
wela=1;
wela=0;
delay(5);
}

void main()
{
TMOD=0x01;
TR0=1;
TH0=(65536-46080)/256;// 由于晶振为11.0592,故所记次数应为46080，计时器每隔50000微秒发起一次中断。
TL0=(65536-46080)%256;//46080的来历，为50000*11.0592/12
ET0=1;
EA=1;
while(1)
{
if(m==20)
{ m=0;
s--;
}
a0=s%10;
a1=s/10;
display(a1,a0);
if(s==0)
{
TR0=0;//时间到，定时器关闭
beep=0;//蜂鸣器响，报时。
}
}
}

void time0() interrupt 1
{TH0=(65536-46080)/256;
TL0=(65536-46080)%256;
m++;
}

ID:72751 · 发表于 2015-1-26 11:33

楼主有点不明白你的意思的，至少使用5位的数码管才能显示出你要的这种形式啊，前两位是分钟，后两位代表秒，是这意思吗？这个程序显示的000：00,你可以自己把高位的0去掉，变成00：00
#include"reg52.h"

#define uchar unsigned char
#define uint unsigned int

sbit DULA = P2^6;  //74H573控制位，控制数码管段码输出
sbit WELA = P2^7;  //74H573控制位，控制数码管位码输出

uchar minute = 0;
uchar second = 0;
uchar T0RH = 0;
uchar T0RL = 0;
uint cnt = 0; //秒计数器
uchar LedBuff[6] = {0X00,0X00,0X00,0X00,0X00,0X00};       //数码管显示缓冲区
uchar code LedChar[] = { //数码管显示编码表
      0X3F,0X06,0X5B,0X4F,0X66,0X6D,0X7D,0X07,  //0~7
      0X7F,0X6F,0X77,0X7C,0X39,0X5E,0X79,0X71,0X09 //8~15 :
};

void ConfigTimer0(uint ms);       //定时器0初始化，确定定时时间
void LedShow(uchar minute,uchar second);

void main()
{
      EA = 1;
      ConfigTimer0(1); //初始化定时器0，定时时间1ms
      while(1)
      {
            if(cnt>=1000)
            {
                     cnt = 0;
                     second++;
                     if(second>=60)
                     {
                              second = 0;
                              minute++;
                              if(minute>=2)
                              {
                                    minute = 0;
                              }
                     }
            }
            LedShow(minute,second);
      }
}

void ConfigTimer0(uint ms)
{
      unsigned long temp;
      temp = 11059200/12;
      temp = temp*ms/1000;
      temp = 65536 - temp;
      T0RH = (uchar)(temp>>8);
      T0RL = (uchar)temp;
      TMOD &= 0XF0;
      TMOD |= 0X01;
      TH0 = T0RH;
      TL0 = T0RL;
      TR0 = 1;
      ET0 = 1;
}

void LedShow(uchar minute,uchar second)
{
      uchar buff[6];
      uchar i;
      buff[0] = second%10;
      buff[1] = second/10;
      buff[2] = 16;
      buff[3] = minute%10;
      buff[4] = minute/10;
      buff[5] = 0;
      for(i=0;i<6;i++)
      LedBuff[ i] = LedChar[buff[ i]];

}
void LedScanf()
{
      static uchar i = 0;
      P0 = 0X00;
      DULA = 1;
      P0 = LedBuff[ i];
      DULA = 0;
      P0 = 0XFF;
      WELA = 1;
      P0 = ~(0X20>>i);
      WELA = 0;
      i++;
      if(i>5)
      i = 0;
}

void interrupttimer0() interrupt 1
{
      TH0 = T0RH;
      TL0 = T0RL;
      LedScanf();
      cnt++;
}

ID:1 · 发表于 2015-1-28 15:37

wind02072107 发表于 2015-1-26 11:33
楼主有点不明白你的意思的，至少使用5位的数码管才能显示出你要的这种形式啊，前两位是分钟，后两位代表秒 ...

[ i ]导致了斜体现在已经修正了.

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求教！如何把倒计时60s的程序改成“00：00”用4位led显示的2分钟程序

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