求16*16LED点阵原理

ID:99188 · 发表于 2016-6-19 19:17

求哪位好心学长给基于51单片机的16*16LED点阵原理及程序。要有详细的过程讲解。

ID:1 · 发表于 2016-6-19 21:01

还是先看下单片机点阵显示的详细教程吧：http://www.51hei.com/bbs/dpj-19894-1.html

ID:99188 · 发表于 2016-6-20 08:40

谢谢主人。太感谢了。

ID:111634 · 发表于 2016-6-20 21:57

本帖最后由 zl2168 于 2016-6-20 21:58 编辑

实例66 LED 16×16点阵显示汉字

先Proteus仿真一下，确认有效。

实例66a LED 16×16点阵汉字显示.rar (48.21 KB, 下载次数: 32)

ID:127660 · 发表于 2016-6-22 13:17

这个我做过，，，听简单的吧

ID:99188 · 发表于 2017-4-22 16:18

谢谢学长，好久没来单片机论坛了。

ID:122949 · 发表于 2017-4-22 18:05

//Note: 74HC595驱动 // __ __ //Note: MR 主复位接电源正极, OE 使能端,输出有效接电源负极 /*--------------------------------------------*/ #ifndef __74HC595_H__ #define __74HC595_H__ /*--------------------------------------------*/ sbit SD = P1^4; //串行数据输入 sbit ST_CK = P1^5; //存储寄存器时钟输入 sbit SH_CK = P1^6; //移位寄存器时钟输入 /*--------------------------------------------*/ //数码管断码和位码的定义 //unsigned char code seg[]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90,0x88,0x83,0xc6,0xa1,0x86,0x8e,0x00,0xff}; //0 1 2 3 4 5 6 7 8 9 a b c d e f 8 无 //unsigned char code pos[]={0x01,0x02,0x04,0x08,0x10,0x20,0x40,0x80}; //1 2 3 4 5 6 7 8 /*--------------------------------------------*/ //函数声明 void Ser_IN(unsigned char Data); //串行数据输入 void Par_OUT(void); //串行数据输出 //void Ser_Par(unsigned char Data); //串行输入,并行输出 /*--------------------------------------------*/ //串行数据输入 void Ser_IN(unsigned char Data) { unsigned char i; for(i = 0; i < 8; i++) { SH_CK = 0; //CLOCK_MAX=100MHz SD = Data & 0x80; Data <<= 1; SH_CK = 1; } } /*--------------------------------------------*/ //并行数据输出 void Par_OUT(void) { ST_CK = 0; ST_CK = 1; } /*--------------------------------------------*/ //串行输入,并行输出 /*void Ser_Par(unsigned char Data) { Ser_IN(Data); Par_OUT(); } */ /*--------------------------------------------*/ #endif

ID:122949 · 发表于 2017-4-22 18:06

#include <AT89X52.H> #include "74HC595.H" unsigned char code tab[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f}; unsigned char code digittab[10][8]={ //字模取模方式阴码逆向逐列式 {0x00,0x00,0x3E,0x41,0x41,0x3E,0x00,0x00},/*"0",0*/ {0x00,0x00,0x42,0x7F,0x40,0x00,0x00,0x00},/*"1",1*/ {0x00,0x00,0x62,0x51,0x49,0x46,0x00,0x00},/*"2",2*/ {0x00,0x00,0x22,0x49,0x49,0x36,0x00,0x00},/*"3",3*/ {0x00,0x00,0x38,0x26,0x7F,0x20,0x00,0x00},/*"4",4*/ {0x00,0x00,0x4F,0x49,0x49,0x31,0x00,0x00},/*"5",5*/ {0x00,0x00,0x3E,0x49,0x49,0x32,0x00,0x00},/*"6",6*/ {0x00,0x00,0x03,0x71,0x09,0x07,0x00,0x00},/*"7",7*/ {0x00,0x00,0x36,0x49,0x49,0x36,0x00,0x00},/*"8",8*/ {0x00,0x00,0x26,0x49,0x49,0x3E,0x00,0x00},/*"9",9*/ }; unsigned int timecount; unsigned char cnta; unsigned char cntb; void main(void) { TMOD=0x01; TH0=(65536-1000)/256; TL0=(65536-1000)%256; TR0=1; ET0=1; EA=1; while(1); } void t0(void) interrupt 1 using 0 { TH0=(65536-1000)/256; TL0=(65536-1000)%256; Ser_IN(tab[cnta]);//8X8点阵列扫描 Ser_IN(digittab[cntb][cnta]);//8X8点阵行送扫描数据 Par_OUT();//74HC595输出显示 cnta++; if(cnta==8) { cnta=0; } timecount++; if(timecount==1000) { timecount=0; cntb++; if(cntb==10) { cntb=0; } } }

ID:122949 · 发表于 2017-4-22 18:07

宁波府尹发表于 2017-4-22 18:06
#include #include "74HC595.H" unsigned char code tab[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f}; ...

这是我用595做的8*8点阵显示0-9的代码

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